If sec0+tan0=p,then find the value of cosec0.
1 answer:
Answer:
Step-by-step explanation:
p=sec0+tan0
=1/cos0 + sin0/cos0
=(1+sin0)/cos0
square both sides
(1+sin)^2 /cos^2 = p^2
(1+sin)^2/(1 - sin^2 ) = p^2
(1+sin)^2/((1-sin)(1+sin)) = p^2
(1+sin)/(1-sin)=p^2
1+sin=p^2-p^sin
sin+p^2sin=p^2-1
sin(1+p^2)=(p^2-1)
sin=(1-p^2)/(1+p^2)
cosec=1/sin
=(1+p^2)/(1-p^2)
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