Question

What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12?

Answer 1

Well, we need to solve the inequality in terms of x...

-3(6-2x)≥4x+12  carry out indicated multiplication on left side

-18+6x≥4x+12  subtract 4x from both sides

-18+2x≥12  add 18 to both sides

2x≥30  divide both sides by 2

x≥15, in interval notation:

x=[15, +oo)