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dusya [7]
3 years ago
8

What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12?

Mathematics
1 answer:
jeka943 years ago
5 0
Well, we need to solve the inequality in terms of x...

-3(6-2x)≥4x+12  carry out indicated multiplication on left side

-18+6x≥4x+12  subtract 4x from both sides

-18+2x≥12  add 18 to both sides

2x≥30  divide both sides by 2

x≥15, in interval notation:

x=[15, +oo)
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3.
saveliy_v [14]

Answer: -4.96x + 6

Step-by-step explanation:

In this problem, it wants you to multiply the -0.4 by the numbers in the parentheses. Don’t let the X confuse you. This is just a placeholder for an unknown number. So first you would multiply the -0.4 into the 10.2, And once you get your answer, just add the X to the end. Which is -4.08x. Then, you would do the same thing, multiply the -0.4 (the number outside of the parenthesis, only with the -15 now. Which gets you 6. Lastly, you take the -0.4 once more and multiply it by the 2.2x. Which gets you -0.88.


-0.4 (10.2x-15+2.2x)

= - 4.08x +6 -0.88x

Now that you have this problem, combined like terms. What are the like terms in this problem?

The -4.08x can be combined with the -0.88 which gets you -4.96. Bring the +6 down, and that gets you your answer of -4.96 +6.


-4.08x -0.88x +6

= -4.96x +6


This would be your final answer because nothing further can be done at this point.


hope this helps!

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