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3 years ago

HELP ME PLEASE I BEG YOU

Mathematics

1 answer:

spayn [35]3 years ago

5 0

Answer:

∠ K = 35° and ∠ L = 105°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

let ∠ K = x then ∠ L = 3x

Sum the angles and equate to 180

3x + x + 40 = 180, that is

4x + 40 = 180 ( subtract 40 from both sides )

4x = 140 ( divide both sides by 4 )

x = 35

Thus

∠ K = 35° and ∠ K = 3x = 3 × 35 = 105°

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There are 5 red marbles, 8 blue marbles, and 12 green marbles in a bag.

cricket20 [7]

To find the percentage always multiply whatever decimal number you have by 100% 
1) 5 + 8 + 12 = 25 (total number in bag)
5/25 x 100% (because you're trying to find probability of red)
= 20%

2) 5 + 8 = 13 (# of red AND blue)
13/25 x 100% (divide out of the total)
=52%

3) 5/25 = 0.2 x 12/25 = 0.48 (find probability of drawing red and green)
0.2 x 0.48 x 100%
= 9.6%

4) 10 + 12 + 28 = 50 (to find total number of trials)
28/50 x 100%
= 56%

5) 5 x 7 (number of sections on first spinner multiply by # of sections on second spinner)
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3 0

4 years ago

Read 2 more answers

A graphing calculator is recommended. A function is given. g(x) = x4 − 5x3 − 14x2 (a) Find all the local maximum and minimum val

Taya2010 [7]

Answer:

The local maximum and minimum values are:

Local maximum

$g(0) = 0$

Local minima

$g(5.118) = -350.90$

$g(-1.368) = -9.90$

Step-by-step explanation:

Let be $g(x) = x^{4}-5\cdot x^{3}-14\cdot x^{2}$ . The determination of maxima and minima is done by using the First and Second Derivatives of the Function (First and Second Derivative Tests). First, the function can be rewritten algebraically as follows:

$g(x) = x^{2}\cdot (x^{2}-5\cdot x -14)$

Then, first and second derivatives of the function are, respectively:

First derivative

$g'(x) = 2\cdot x \cdot (x^{2}-5\cdot x -14) + x^{2}\cdot (2\cdot x -5)$

$g'(x) = 2\cdot x^{3}-10\cdot x^{2}-28\cdot x +2\cdot x^{3}-5\cdot x^{2}$

$g'(x) = 4\cdot x^{3}-15\cdot x^{2}-28\cdot x$

$g'(x) = x\cdot (4\cdot x^{2}-15\cdot x -28)$

Second derivative

$g''(x) = 12\cdot x^{2}-30\cdot x -28$

Now, let equalize the first derivative to solve and solve the resulting equation:

$x\cdot (4\cdot x^{2}-15\cdot x -28) = 0$

The second-order polynomial is now transform into a product of binomials with the help of factorization methods or by General Quadratic Formula. That is:

$x\cdot (x-5.118)\cdot (x+1.368) = 0$