Please help i dont know what to do :(

Lunna [17]

A since 19 x 29= 551 and 551/375 is around 1.5

4 0

3 years ago

PLS HELP ASAP PLS IF YOU DO THANK YOU SOSOSOSOOSOS MUCH Find the measure of angle x. Round your answer to the nearest hundredth.

Lina20 [59]

Answer:

61.93

Step-by-step explanation:

use cosine x= 8/17

4 0

3 years ago

The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for hou

o-na [289]

This question s incomplete, the complete question is;

The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.

There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour

Answer:

The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

Step-by-step explanation:

Given the data in the question;

let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively

so

x + y = 55 ----------------equ1

x = 55 - y ------------------qu2

also

15x + 30y = 1050

x + 2y = 70 --------------equ3

input equ2 into equ3

(55 - y) + 2y = 70

- y + 2y = 70 - 55

y = 15

input value of y into equ1

x + 15 = 55

x = 55 - 15

x = 40

Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

8 0

3 years ago

Try It for Example 3: Is 3.14144144414444... a rational number? Explain your reasoning. *

chubhunter [2.5K]

it's irrational

A rational number can be put over a fraction, while this number continues forever

5 0

3 years ago

Read 2 more answers

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

5 0

2 years ago