Please help i dont know what to do :(

Please write the function(x) from the given rules:a. Twice the input value plus three. B. The input value minus five. C. To get

Bas_tet [7]

Answer:

A) f(x) = 2x + 3

B) f(x) = x - 5

C) f(x) = 2x + 4

Step-by-step explanation:

To find - Please write the function(x) from the given rules:

A) Twice the input value plus three.

B) The input value minus five.

C) To get the output, multiply the input by two, then add four.

Proof -

Let us assume that the input = x

The output = f(x)

Now,

A)

f(x) = 2x + 3

B)

f(x) = x - 5

C)

f(x) = 2x + 4

8 0

3 years ago

Chivis Mexican restaurant pledges 12% of any food purchased on the thrid Wednesday of each month to the cystic fibrosis foundati

Dmitrij [34]

Answer:

food purchased= $9,600

Step-by-step explanation:

Giving the following information:

Chivis Mexican restaurant pledges 12% of any food purchased

Minimum donation= $1,152

<u>To calculate the food to be purchased, we need to use the following formula:</u>

Donation= food purchased*0.12

1,152= food purchased*0.12

1,152/0.12= food purchased

food purchased= $9,600

3 0

4 years ago

From $2003$ onward, the number of daily visitors to a website increased by $200\%$ every two years. So, for example, the number

andrew-mc [135]

Answer:

2007

Step-by-step explanation:

If the number of visitors was, say, 100 people in 2003, then in 2005 that number would have gone up to 300 people, which is a 200% increase. And that number would have gone up to 900 people in 2007, which is an 800% increase.

5 0

3 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

This is the last question which is the fifth one if you can PLS HELP

Trava [24]

I think the answer is b

3 0

2 years ago

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