Answer:
-5
Step-by-step explanation:
Moving all terms of the quadratic to one side, we have
.
A quadratic has one real solution when the discriminant is equal to 0. In a quadratic 
, the discriminant is 
.
(The discriminant is more commonly known as 
, but I changed the variable since we already have a 
in the quadratic given.)
In the quadratic above, we have 
, 
, and 
. Plugging this into the formula for the discriminant, we have
.
Using the distributive property to expand and simplifying, the expression becomes
Setting the discriminant equal to 0 gives
.
We can then solve the equation as usual: first, divide by 2 on both sides:
.
Squaring both sides gives
,
and subtracting 5 from both sides, we have
N 2-1 < 3
n is equal to :
2-1 = 1 so n would have to be 1 in order to be less than 3
1. 81 1/2 = 163/2
2. 32 1/5 - 64 1/3 =
483/15 - 965/15 =
-482/15 or -32 2/15
3. 16 1/4 = 65/4
4. 49 1/2 + 27 1/3 =
99/2 + 82/3 =
297/6 + 164/6 =
461/6 or 76 5/6
Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
Answer: option d.
Step-by-step explanation:
We have the function:
y = f(x) = x^2 - 1
The output is 99 when y = 99, and the input is x.
Then we need to solve:
y = 99 = x^2 - 1
for x.
99 = x^2 - 1
99 + 1 =x^2
100 = x^2
√100 = x
10 = x
The correct option is d, input equals 10.
