The best way to do this is to draw a picture of ΔFKL and include line segment KM that is perpendicular to FL. This creates ΔFKM which is a 45°-45°-90° triangle and ΔLKM which is a 30°-60°-90° triangle.
Find the lengths of FM and ML. Then, FM + ML = FL
<u>FM</u>
ΔFKM (45°-45°-90°): FK is the hypotenuse so FM = 
<u>ML</u>
ΔLKM (30°-60°-90°): from ΔFKM, we know that KM = 
, so KL = 
<u>FM + ML = FL</u>
= 
52.9109 in pounds if that's what your asking.
Answer:
(a) 860, (b) 860, (c) 860 and 186
Step-by-step explanation:
(a) 860
860 ends with a zero or a five, 186 and 863 do not.
(b) 860
860 ends with a zero, 186 and 863 do not.
(c) 860, 186
860, the 0 is even. 186, the 6 is even. 863, the 3 is not even.
The slope of the function for pronghorn antelope is 60.78 which infers that the rate of speed of the pronghorn is 60.78 miles per hour.
7) The given function that represents the speed of the pronghorn is
y = 60.78x - 5.4
Comparing this function with the general equation of a straight line
y = mx + c we can conclude that the slope of the function is 60.78 .
So the Pronghorn's rate of speed is 60.78 miles per hour.
8) Now the speed of the cheetah is given in the form of a table.
Let us take any two points on the graph
(0.5,21.85) and (2,118.60)
Slope of the line passing through these two points
= (118.6-21.85)/(2-0.5)
=64.5
So the slope of the graph is 64.5 and the average rate of speed of the Cheetah is 64.5 miles per hour.
9) From the above two slopes and the rate of speed we can conclude that the speed of the cheetah is 64.5 mph which is greater than that of the pronghorn 's speed of 60.78 miles per hour.
To learn more about slope visit:
brainly.com/question/13281781
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