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Gre4nikov [31]
2 years ago
13

Can anyone help me with this and let me know how to enter this on my calculator, please? It doesn’t seem to give me the correct

answer when there’s a decimal place. Will mark branliest!

Mathematics
1 answer:
Drupady [299]2 years ago
5 0

Answer:

0.036

Step-by-step explanation:

<em>The </em><em>diameter</em><em> </em><em>is </em><em>0</em><em>.</em><em>6</em><em>/</em><em>2</em><em>,</em><em> </em><em>which </em><em>is </em><em>0</em><em>.</em><em>3</em><em> </em><em>and </em><em>your </em><em>radius </em><em>is </em><em>0</em><em>.</em><em>3</em><em>.</em>

<em>on </em><em>your </em><em>calculator</em><em> </em><em>,</em><em> </em><em>you'll</em><em> </em><em>press </em><em>4</em><em>/</em><em>3</em><em> </em><em>×</em><em> </em><em>0</em><em>.</em><em>3</em><em>^</em><em>3</em>

<em>which </em><em>is </em><em>equals </em><em>to </em><em>0</em><em>.</em><em>0</em><em>3</em><em>6</em><em>π</em>

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Estimate by rounding to the nearest hundred.<br>Show your work.<br>12,846 - 3467​
Rufina [12.5K]

Answer:

9,400

Step-by-step explanation:

12,846 - 3,467 = 9,379

The hundreds digit is 3.

So, you look to the left of the digit and if it is 5 for more you add a number to the 3 and make the rest of the digits 0s. But if it below 5, then you leave the 3 alone and make the rest of the digit going to the right 0s.

Then, your answer is (9,400)

Hope this helps ; )

3 0
3 years ago
The rectangle shown has a perimeter of 54 cm and the given area. Its length is 3 more than 3 times its width. Write and solve a
algol13

Answer:

Step-by-step explanation:

the perimeter P=2(L+W)=54

P=2L+2W=54 OR L+W=27

we know that L=3W+3

P=3W+W=27-3

4W=24

W=6 CM

L=21CM

5 0
3 years ago
Which number has the prime factorization 5 · 72 · 32?
lubasha [3.4K]

Answer:

see below

Step-by-step explanation:

5*72*32 is not a prime factorization to begin with because neither 72, nor 32 are primes. A prime factorization for this product would be:

2*2*2*2*2*2*2*2*3*3*5

and the number with this factorization is 11520.

There is a small chance that what you meant to write was this: 5\cdot 7^2 \cdot 3^2 in which case the number for this prime factorization is 2205.

5 0
3 years ago
Read 2 more answers
Find the surface area of the pyramid round to the nearest tenth choose the correct unit
sineoko [7]

slant height(h) = 16.3ft

Base side = 20ft

\text{Area of pyramid=}\frac{1}{2\text{ }}\times perimeterofbase\text{ x slant height}

Perimeter of base = 4(base side) = 4(20) = 80ft

\begin{gathered} \text{Area of pyramid = }\frac{1}{2}\times80\times16.3 \\ \text{Area = }652ft^2 \end{gathered}

7 0
9 months ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
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