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3 years ago

Can someone help me please solving these maths problems thanks.

Mathematics

2 answers:

blondinia [14]3 years ago

8 0

2/4 on the 0 to 1 and 5/4 on the 1 to 2

Zielflug [23.3K]3 years ago

4 0

2/4 goes in the first box and 5/4 goes in the second

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Solve two sevenths times four sixths . (2 points) Group of answer choices six forty seconds eight forty seconds six thirteenths

Maksim231197 [3]

Given:

The statement is "two sevenths times four sixths".

To find:

The value of the product.

Solution:

Two sevenths times four sixths can be written as:

$\dfrac{2}{7}\times \dfrac{4}{6}$

It can be rewritten as:

$\dfrac{2}{7}\times \dfrac{4}{6}=\dfrac{2\times 4}{7\times 6}$

$\dfrac{2}{7}\times \dfrac{4}{6}=\dfrac{8}{42}$

The answer of given expression is eight forty seconds.

Therefore, the correct option is B.

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3 years ago

What is the inverse function f(x)=-3x-2

vesna_86 [32]

f^-1 (x) = 2/3 + x/3

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3 years ago

Keisha has a straightedge and a compass, but no protactor. what kind of angle can Keisha drag exactly with only these two tools?

nekit [7.7K]

A 90˚ angle
a 180 angle

6 0

3 years ago

Which ordered pair is a solution of the equation? 2x+4y=6x-y OPTION A: Only (4,5) OPTION B: Only (5,4) OPTION C Both A and B OPT

sammy [17]

Answer:

option b

Step-by-step explanation:

replace x and y with the x and y of the ordered pair

option a: 2(4)+4(5)=6(4)-5

solve

8+20=24-5

28=19 not true

option b:2(5)+4(4)=6(5)-4

solve

10+16=30-4

26=26 true

6 0

3 years ago

What is the simplified form of the following expression? 2√27+√12-3√3-2√12

LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$

but

$2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}$

$\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}$

Since √12=2√3,this implies that,

$2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}$

Therefore,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}$

$=(6+2-3-4)\sqrt{3}$

$=\sqrt{3}$

The simplified form of ,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$ is √3

8 0

3 years ago