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jenyasd209 [6]
3 years ago
15

Can someone help me please solving these maths problems thanks.

Mathematics
2 answers:
blondinia [14]3 years ago
8 0
2/4 on the 0 to 1 and 5/4 on the 1 to 2
Zielflug [23.3K]3 years ago
4 0
2/4 goes in the first box and 5/4 goes in the second
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URGENT pleaseee help 10 points and brainlist if right!!!!<br> Use the Sohcahtoa method!!
Vsevolod [243]

Answer: x is 36 degrees

Step-by-step explanation:

To solve this triangle, we can use sin -1 x = 14 / 24. This gives us 35.69 degrees, but in your answer choices you only get integers. We can round this up to 36 degrees to get the answer.

8 0
2 years ago
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Which is the equation of the line with slope 2 that passes through (8,14).
Brut [27]
B. y = 2x-2

14 = 2(8) + b
14 = 16 + b
-2 = b
7 0
3 years ago
Rewrite each expression by combining like terms.<br><br> 8pq - 3pq<br><br> 2m - 3m + 4
qaws [65]

Answer:

  1. 8pq-3pq= 5pq
  2. 2m-3m+4 =4-m

Step-by-step explanation:

  1. The first equation shows two terms can be combine as follow: 8pq-3pq= (8-3)pq by applying common factoring. Then, because 8-3=5, it can be expressed as 5pq.
  2. In the second equation, we have only two terms that can be factored by combining the terms that share the same factor (which is m). Then, 2m-3m+4 can be expressed like m(2-3)+4. Because (2-3)=-1 and because the order of the sum does not affect the result, the result is 4-m.
4 0
3 years ago
. A man bought a car for $60 320. After using it for 2 years he decides to trade in the car. The company estimated a depreciatio
Veronika [31]

Answer:

(a) 39,208

(b) 65%

Step-by-step explanation:

(a) The car loses 10% the first year and 15% the second year so that’s 35% lost in total after two years.

35% of 60,320 is 21,112

60,320 - 21,112 = 39,208

39,208 ÷ 60,320 = 0.65 (65%)

8 0
2 years ago
Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)
vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

5 0
2 years ago
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