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ElenaW [278]
2 years ago
6

Plzz help and no wrong answer need to be done asap

Mathematics
1 answer:
Ann [662]2 years ago
7 0

Answer:

1/500

Step-by-step explanation:

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is it 20% I'm not really sure

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3 years ago
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What is the domain of the function y = l n (StartFraction negative x 3 Over 2 EndFraction).
Ymorist [56]

The domain of the provide function where the function is defined is x less than the number three.

<h3>What is the domain of the function?</h3>

Domain of a function is the set of all the possible input values which are valid for that function.

The function given in the problem is,

y=\ln\left(\dfrac{-x+3}{1}\right)

The above function is the function of logarithm. For the logarithmic function, it is defined for all the real numbers except 0.

Thus, the function should be greater than zero as,

\left(\dfrac{-x+3}{1}\right) > 0\\(-x+3) > 0\\-x > -3

Change the sign of both side, by changing the inequality,

x < 3

Thus, the domain of the provide function where the function is defined is x less than the number three.

Learn more about the domain of the function here;

brainly.com/question/2264373

3 0
2 years ago
Can I have help with these? Picture attached.
8_murik_8 [283]

Answer:

5. mCD is 27.8°  |  7. mAFC 52.3° |

Step-by-step explanation:

8 0
3 years ago
-2x-y-2z+4x-2y+3z<br> Please help
sdas [7]

Answer:

2x-3y+z

Step-by-step explanation:

-2x-y-2z+4x-2y+3z

combine like terms

-2x+4x= 2x

-y-2y= -3y

-2z+3z= z

so..

2x-3y+z

8 0
3 years ago
To find the extreme values of a function​ f(x,y) on a curve xequals​x(t), yequals​y(t), treat f as a function of the single vari
pychu [463]

Answer:

Absolute maximum is 2  

Absolute minimum at -2

Step-by-step explanation:

The given parametric functions are:

x=2\cos t,y=2\sin t

By the chain rule:

f'(t)=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }

\frac{df}{dt} =\frac{2 \cos t}{-2\sin t} =-\cot(t)

At fixed points, f'(t)=0

\implies -\cot (t)=0

This gives t=\frac{\pi}{2} ,\frac{3\pi}{2} on 0\le t\le 2\pi

This implies that the extreme points are (2\cos \frac{\pi}{2}, 2\sin \frac{\pi}{2})=(0,2) and (2\cos \frac{3\pi}{2}, 2\sin \frac{3\pi}{2})=(0,-2)

By eliminating the parameter, we have x^2+y^2=4

This is a circle with radius 2, centered at the origin.

Hence (0,2) is an absolute maximum ,at t=\frac{\pi}{2} and (0,-2) is an absolute minimum at  t=\frac{3\pi}{2}

7 0
3 years ago
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