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ElenaW [278]
2 years ago
6

Plzz help and no wrong answer need to be done asap

Mathematics
1 answer:
Ann [662]2 years ago
7 0

Answer:

1/500

Step-by-step explanation:

You might be interested in
According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0
3 years ago
Translate the sentence into an equation. Twice the difference of a number and 6 is 2.
mojhsa [17]

Answer:

let the number be x.

  • 2(x-6)=2

hope it helps

<h2>stay safe healthy and happy....</h2>
7 0
3 years ago
Sunflower growth 1 week it grew 2 and va half inches in two weeks it grew 2 and 3 fourth in 3 weeks it grew 3 and one fourth how
Liula [17]

Answer:

The Growth of sunflower duing 3 weeks is 8.5 inches or 8 (1/2).

Step-by-step explanation:

Given:

Growth of sunflower each week .

To find :

Total growth during 3 weeks?

Solution:

According to given data:

Growth is

  1. 1st week=2 and 1/2 inches=5/2=2.5 inches .
  2. 2nd week =2 and 3/4 inches=11/4 inches.
  3. 3rd week=3 and 1/4 inches=13/4  inches.

Total growth is given by,

=growth of (1st week +2 week+ 3 week)

=5/2+11/4+13/4

=34/4

=17/2

=8 and 1/2 inches.

Hence the overall growth is about 17/2 or 8.5 inches in 3 weeks .

6 0
3 years ago
This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,
Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Person has the flu.
  • Event B: Person got the flu shot.

The percentages associated with getting the flu are:

  • 20% of 30%(got the shot).
  • 65% of 70%(did not get the shot).

Hence:

P(A) = 0.2(0.3) + 0.65(0.7) = 0.515

The probability of both having the flu and getting the shot is:

P(A \cap B) = 0.2(0.3) = 0.06

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0
2 years ago
Explain answer !! <br><br> ( WILL GIVE BRAINLEST)
Ganezh [65]

Answer:find the solution to the system of equations below.start by adding the equation

{-2x+2y=-8

{2x+y=5

Step-by-step explanation:The given system of equation are:

1----  y= x -4

2----- y=4 x+2

Equation (1) - Equation (2)

→0= x -4 - (4 x+2)

→0=  -3 x -6-----[Adding and subtracting like terms]

Adding 3 x on both sides

→3 x= -6

Dividing by 3 on both sides

→x = -2

→Substituting the value of x in equation 1, we get

y= -2 -4

y =-6

→Solution set =(x,y)=(-2, -6)

Don't used the graph to find the solution.

4 0
3 years ago
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