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Mumz [18]
3 years ago
15

Which statement correctly describes the relationship between an acute and obtuse angle? An acute angle has the same measure as a

n obtuse angle. An acute angle has a greater measure than an obtuse angle. An acute angle has a smaller measure than an obtuse angle. An acute angle and an obtuse angle add together to make a right angle.
Mathematics
2 answers:
SSSSS [86.1K]3 years ago
8 0
An acute angle has a smaller measure than an obtuse angle

Arturiano [62]3 years ago
3 0

Answer: C) An acute angle has a smaller measure than an obtuse angle.

Step-by-step explanation: An obtuse angle is more than 90deg but less than 180deg. An acute angle is an angle smaller than a right angle. The range of an acute angle is between 0 and 90 degrees. So the correct answer is the corresponding to optin C: An acute angle has a smaller measure than an obtuse angle (if we add together an obtuse and an acute angle it will always be more than 90deg).

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Find the average value of the function f(t)=(t-2)^2 on [0,6]
pentagon [3]

Answer:

2

Step-by-step explanation:

The "average value of function f(x) on interval [a, b] is given by:

                      f(b) - f(a)

ave. value = ---------------

                         b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2.  For b = 6, we get:

          f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16

For a = 0, we get:

           f(0) = (0 - 2)^2 = 4

Plugging these results into the ave. value function shown above, we get:

                      16 - 4

ave. value = ------------ = 12/6 = 2

                         6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.


4 0
3 years ago
Ms. Dunn spent 10.70 buying slices of pie and cookies. She bought a total of 24 items. A slice of pie costs 0.80 and a cookie co
Rus_ich [418]

Answer:

Ms. Dunn bought 7 slices of pie.

Step-by-step explanation:

With the information provided, you can write the following equations:

x+y=24 (1)

0.80x+0.30y=10.70 (2), where:

x is the number of slices of pie

y is the number of cookies

First, you can solve for x in (1):

x=24-y (3)

Next, you have to replace (3) in (2) and solve for y:

0.80(24-y)+0.30y=10.70

19.2-0.80y+0.30y=10.70

19.2-10.70=080y-0.30y

8.5=0.5y

y=8.5/0.5

y=17

Finally, you can replace the value of y in (3) to be able to find the value of x:

x=24-17

x=7

According to this, the answer is that Ms. Dunn bought 7 slices of pie.

7 0
3 years ago
A jar contains only​ pennies, nickels,​ dimes, and quarters. There are 23 ​pennies, 22 ​dimes, and 20 quarters. The rest of the
goldfiish [28.3K]

<em>Answer:</em>

<em>1. 65 coins</em>

<em>2. 79 - (23 + 22 + 20) = n</em>

<em>Step-by-step explanation:</em>

<em>You can use the expression 23 + 22 + 20 to get the amount of coins that are not nickles. And for two? Try it yourself.</em>

<em>Hope this helps. Have a nice day.</em>

8 0
3 years ago
What is 92 divided by 2?
Vikentia [17]
46. Fortysix times 2 equals 92.
8 0
3 years ago
Find all solutions of the equation: 2cos^2x-cosx=1
Art [367]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

——————————

Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

     \mathsf{2t^2-t-1=0}


Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

     \mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}


Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

3 0
3 years ago
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