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1 year ago

Which rational exponent represents a square root?

Mathematics

1 answer:

Viefleur [7K]1 year ago

7 0

Answer:

1/2 rational exponent represents a square root.

Step-by-step explanation:

Because it is an example of a true square root.

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Radio signals travel at a rate of 3 × 108 meters per second. How many seconds will it take for a radio signal to travel from a s

lys-0071 [83]

Answer:

1.1888 (8 goes on forever) seconds to travel from the satellite to Earth.

Step-by-step explanation:

It is traveling at 3 x 108 m/s and needs to travel 3.6 x 107 m. 3 x 108=324 and 3.6 x 107=385.2 so 324 m/s for 385.2 m. 385.2/325=1.1888.

5 0

2 years ago

Read 2 more answers

(8, 1) and (-1, 10)<br> Slope

gizmo_the_mogwai [7]

Answer:

<h2>The answer is 1</h2>

Step-by-step explanation:

The slope of the line between two points can be found by using the formula

$m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1}$

where

(x1 , y1) and (x2 , y2) are the points

From the question is points are

(8, 1) and (-1, 10)

Substitute the values into the above formula and solve for the slope

That's

$m = \frac{10 - 1}{8 + 1} \\ = \frac{9}{9} = 1$

We have the final answer as

Hope this helps you

7 0

2 years ago

What is a two column proof

ruslelena [56]

A, the first choice. c doesn't say tht its in a logical flow

3 0

2 years ago

Read 2 more answers

A rope is tied to the bottom of a hot air balloon as shown below. The rope makes an angle of 35 degrees with the ground distant

Serjik [45]

We have a right triangle. We know the hypotenuse (75 ft) and an angle of 35°. We need to find the opposite leg to the angle of 35° (h). The trigonometric function that relates the opposite leg to an angle with the hypotenuse is sine:
sin 35° = (Opposite leg to 35°) / hypotenuse
sin 35° = h/(75 ft)

Solving for h:
(75 ft) sin 35°=h
h=75 sin 35° ft
h=75 (0.573576436) ft
h=43.01823270 ft
h=43 ft

Answer: T<span>he bottom of the balloon is 43 ft from the ground</span>

8 0

2 years ago

You work in a chemical lab. Last quarter, you successfully completed an average of about 5 chemical analyses per day. This quart

Kryger [21]

Answer: 60%

Step-by-step explanation:

Since, According to the question, Last quarter, we successfully completed an average of about 5 chemical analyses per day.

Therefore initially our average = 5 chemical analyses per day.

Again, From the question, This quarter, we have increased this average to about 8 per day.

Therefore New average =chemical analyses 8 per day

Thus, Percentage change in the average = (Initial average - New average)×100/ initial average

= $\frac{8-5}{5} \times 100$