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agasfer [191]
2 years ago
5

Which rational exponent represents a square root?

Mathematics
1 answer:
Viefleur [7K]2 years ago
7 0

Answer:

1/2 rational exponent represents a square root.

Step-by-step explanation:

Because it is an example of a true square root.

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Which of these equations best describes the line of best fit for the data in the scatter plot on the number of metals the U.S. O
Fed [463]

Answer:

B

Step-by-step explanation:

It's not going negative you can tell by the line it has y-intercept and the last on didn't the other ones have aa negative. If you have a problem with these kinds of equations just do process of elimination and you'll be fine also here's the answer to another question

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4 years ago
PLEASE HELP ILL GOVE BRAINLIST !!!
PSYCHO15rus [73]

The tree is 16 ft tall.

4/6=x/24

If you make the denominators the same you will find your answer which is 16 ft tall.

6 0
3 years ago
2. R = PN + C<br> Solve for (N)
Galina-37 [17]

Answer:

N=R/P−C/P

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

5 0
4 years ago
Function f is defined by f(x)=3/2x+c. If f(6)=1, what is the value of f(c)?
ASHA 777 [7]

Answer:

C = - 8

Step-by-step explanation:

f(x) =  \frac{3}{2} x + c \\  \\ plug \: x = 6 \\  \\ f(6) =  \frac{3}{2}  \times 6 + c \\  \\  f(6) = 3 \times 3 + c \\  \\ f(6) = 9+ c \\  \\  \therefore \: 1 = 9 + c \:  \{ \because \: f(6) = 1 \} \\  \\ 1 - 9 = c \\  \\ \huge \red{ \boxed{ c =  - 8}}\\\\f(c) =\frac{3}{2} c +(-8)\\\\\huge \orange { \boxed{ f(c) =\frac{3}{2} c -8}} \\\\

7 0
3 years ago
can someone help me, Just the answer don’t worry about explaining everything, Im really bad on Math :(
Strike441 [17]

Answer:

a. -2 b. -2 c. -1 d. 4 e. -3 f. 0

Step-by-step explanation:

The average rate of change formula is:

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}

a.  

We need to find the rate of change for x = -3 to x = -2 so we look on the graph to find y.

At x = -3 it look like y = 0  so

x_{1} = -3

y_{1} = 0

At x = -2 it looks like y = 2

x_{2} = -2

y_{2} = 2

Now we can just plug everything in to the rate of change formula.

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{2- 0}{-3-(-2)} = \frac{2- 0}{-3+2} = \frac{2}{-1} = -2

So for a. our rate of chage for the given interval is -2

b.

Now that you have the formula we don't need to explain each time.

x_{1} = -2

y_{1} = 2

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4- 2}{1-(-2)} = \frac{-4-2}{1+2} = \frac{-6}{3} = -2

c.

x_{1} = 0

y_{1} = -3

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4-(-3)}{1-0} = \frac{-4 + 3}{1-0} = \frac{-1}{1} = -1

d.

x_{1} = 1

y_{1} = -4

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0 - (-4)}{2-1} = \frac{0 + 4}{2-1} = \frac{4}{1} = 4

e.

x_{1} = -1

y_{1} = 0

x_{2} = 0

y_{2} = -3

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-3- 0}{0-(-1)} = \frac{-3- 0}{0+1} = \frac{-3}{1} = -3

f.

x_{1} = -1

y_{1} = 0

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0- 0}{2-(-1)} = \frac{0- 0}{2+1} = \frac{0}{3} = 0

4 0
3 years ago
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