Answer:
See the code snippet below
Explanation:
import java.util.Scanner;
public class LabProgram{
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
System.out.println("Please enter first number: ");
int firstNumber = scan.nextInt();
System.out.println("Please enter second number: ");
int secondNumber = scan.nextInt();
maxMagnitude(firstNumber, secondNumber);
}
public static int maxMagnitude(int firstValue, secondValue){
System.out.println(Math.max(firstValue, secondValue));
}
}
Answer:
ok done we will try
BTW have a nice day enjoy your day Stay blessed stay happy stay strong
Answer: an audio file containing speech
Explanation:
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}