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Alex787 [66]
3 years ago
9

Convert (520)10 into base 16​

Computers and Technology
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

The base-10 value of 52010 is equal to base-16 value of 20816.

Explanation:

kakasveta [241]3 years ago
3 0
The base-10 value of 52010 is equal to base-16 value of 20816.
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In an office there is a unisex bathroom with n toilets. The bathroom is open to both men and women, but it cannot be used by men
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Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <stdlib.h>

#include <pthread.h>

#include <semaphore.h>

int mcount,wcount;

sem_t x,y,z,wsem,msem,cap;

void delay(void)

{

int i;

int delaytime;

delaytime = random();

for (i = 0; i<delaytime; i++);

}

void *woman(void *param)

{

sem_wait(&z);

sem_wait(&wsem);

sem_wait(&y);

wcount++;

if(wcount==1)

{ sem_wait(&msem); }

sem_post(&y);

sem_post(&wsem);

sem_post(&z);

sem_wait(&cap);

printf("woman in!\n");

delay();

printf("\twoman out!\n");

sem_post(&cap);  

sem_wait(&y);

wcount--;

if(wcount==0)

{ sem_post(&msem); }

sem_post(&y);

}

void *man(void *param)

{  

sem_wait(&z);

sem_wait(&msem);

sem_wait(&x);

mcount++;

if(mcount==1)

{ sem_wait(&wsem); }

sem_post(&x);

sem_post(&msem);

sem_post(&z);

sem_wait(&cap);

printf("\t\tman in!\n");

delay();

printf("\t\t\tman out!\n");

sem_post(&cap);

sem_wait(&x);

mcount--;

if(mcount==0)

{sem_post(&wsem);}

sem_post(&x);

}

int main(void)

{

int i;

srandom(60);

mcount = 0;

wcount = 0;

sem_init(&x,0,1); // for sem_init, initial value is 3rd argument

sem_init(&y,0,1);

sem_init(&z,0,1);

sem_init(&wsem,0,1);

sem_init(&msem,0,1);

sem_init(&cap,0,4); // eg. cap initialized to 4

pthread_t *tid;

tid = malloc(80*sizeof(pthread_t));

// You can use your cobegin statement here, instead of pthread_create()  

// I have forgone the use of pthread barriers although I suppose they would nicely imitate the functionality of cobegin.

// This is merely to retain simplicity.

for(i=0;i<10;i++)

{

pthread_create(&tid[i],NULL,woman,NULL);

}

for(i=10;i<20;i++)

{  

pthread_create(&tid[i],NULL,man,NULL);

}

for(i=0;i<20;i++)

{  

pthread_join(tid[i],NULL);

}

return(0);

}

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The program outputs the following rectangular array:

0 0 0 0

0 1  2 3

0 2 4 6

0 3 6 9

0 4 8 12

This is the correctly formatted C# program:

namespace ConsoleApp1{

   class Program

   {

       static void Main(string[] args)

       {

           int i, j;    // <em>declare index variables used to iterate over the array A</em>

           int [,] A = new int[5,5];   // <em>create a 5 by 5 array</em>

           

           /*<em> Iterate over the array with the index variables i and j</em>

<em>                and initialize each location A[i, j] with the product </em>

<em>                of i and j.</em> */  

           for (i = 0; i < 5; ++i)

           {

               for (j = 0; j < 4; ++j)

               {

                   A[i, j] = i*j;

               }

           }

           

           /* <em>Iterate over the array again. This time, swap locations </em>

<em>                A[i, j] with A[j, i]</em> */

           for (i = 0; i < 5; ++i)

           {

               for (j = 0; j < 4; ++j)

               {

                   if (i < 5)

                   {

                       A[j, i] = A[i, j];

                   }

                   else

                       break;

                   

                   // <em>display the current location A[i, j]</em>

                   Console.Write(A[i, j] + " ");

                   

               }

               /* <em>print a newline to prepare for the next line of printing</em>

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               Console.WriteLine();

                // <em>pause and wait for user keypress before continuing</em>

               Console.ReadLine();

               

               }

           }

       }

   }

When executed, this program simply prints a rectangular array like so;

0 0 0 0

0 1  2 3

0 2 4 6

0 3 6 9

0 4 8 12

Learn more about predicting program output here: brainly.com/question/20259194

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