Answer:
U1 = U2 since the temperature inside the balloon does not change
Q1 - W1 = Q2 - W2
Work done by the balloon = W2 - W1 (on the environment)
W2 - W1 = Q2 - Q1 = 75 J heat put into balloon
So the balloon does 75 J on the environment
To rearrange these for v and r we must use BEDMAS.
First, times both sides by r, getting Ar = v²r/r
You can cancel out r/r to get Ar = v²
To get v, square root both sides. √Ar = √v²
Cancel out the square root and the squared v = √Ar
To get r, go back to Ar = v², then divide both sides by A. rA/A = v²/A
Then cancel out A/A to get r. r = v²/A
Explanation:
Given that,
Initial velocity, u = 11.3 m/s
Angle above the horizontal,
Time of flight :
Horizontal distance traveled is given by :
x = ut
x = 11.3 m/s × 1.32 s
x = 14.916 m
Maximum height is given by :
Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.
Answer:
60km/hr west
Explanation:
When you are dealing with velocity you always name the direction its going in
The meaning of the word advance is (A.) A movement forward