Question

A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. if it takes 0.070 n of force to keep the beetle moving in a circle on the record, what is the tangential speed of the beetle? 0.68 m/s 0.46 m/s 0.33 m/s 0.11 m/s

Answer 1

The answer is 0.68 meters per second, swagteam

Answer 2

Answer:

Tangential speed is 0.68 m/s

Explanation:

It is given that,

Mass of the beetle, m = 0.023 kg

It is placed at a distance of 0.15 m from the center of record i.e. r = 0.15 m.

If it takes 0.070 n of force to keep the beetle moving in a circle on the record i.e. centripetal force acting on it is, F = 0.070 N

We have to find the tangential speed of the beetle. The formula for centripetal force is given by :

$F=\dfrac{mv^2}{r}$

v is tangential speed

$v=\sqrt{\dfrac{Fr}{m}}$

$v=\sqrt{\dfrac{0.070\times 0.15}{0.023}}$

v = 0.675 m/s

or

v = 0.68 m/s

Hence, the correct option for tangential speed is (A).