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Triss [41]
2 years ago
13

If both lines had been dotted lines instead, how might that have affected the possible solutions?

Mathematics
1 answer:
prisoha [69]2 years ago
5 0

Answer:

Step-by-step explanation:

You will have less possible solution y is less than or y is greater than so everything touching the line will not be a solution just everything else.

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Pedro le dice a María si cambias los billetes de 10 € que tienes por billetes de 5 € y los billetes de 5 € por billetes de 10 €
Bad White [126]

Answer: Maria has 10 bills of 5€ and 10 bills of 10€.

She has a total of 150€.

Step-by-step explanation:

Let be "f" the number of 5€ bills that Maria has and "t" the number of 10€ bills that Maria has.

Set up a system of equations:

\left \{ {{f+t=20} \atop {5f+10t=10f+5t}} \right.

Use the Substitution method to solve the system of equations:

1. Solve for "f" from the first equation:

f=20-t

2. Substitute the equation obtained into the second equation and solve for "t".

Then:

5(20-t)+10t=10(20-t)+5t\\\\100-5t+10t=200-10t+5t\\\\20t-10t=100\\\\t=\frac{100}{10}\\\\t=10

3. Substitute the value of "t" into the equation f=20-t and evaluate:

f=20-10\\\\f=10

Therefore, Maria has 10 bills of 5€ and 10 bills of 10 €.

So the total amount of money she has, is:

Total=10(5)+10(10)=150

She has a total of 150€.

5 0
3 years ago
How do you solve this using a picture and the work?
hoa [83]
Okkk so u need to use the Pythagorean Theorum.
a x^{2} +b x^{2} =c x^{2}

a=x
b=1
c=5

so...
c x^{2} -b x^{2} =a x^{2}

5 x^{2} -1 x^{2} =a x^{2}

Solve that

4 0
3 years ago
Courtney receives a mailer to a local store. In the mailer, there are two coupons which cannot be combined. One coupon is for $2
STatiana [176]

Answer:

B, Courtney should use the 15% off coupon

8 0
3 years ago
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Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro
umka21 [38]

|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%

8 0
3 years ago
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The distance D that a spring is stretched by a hanging object varies directly as the weight W of the object. if a 9-kg object st
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Answer:

I think it is b

Step-by-step explanation:

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3 years ago
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