Is there another way to write 7.05.

Solve the equation. 36^6x-1 = 6^5x

loris [4]

The answer of the question which you asked above is
36^6x-6^5x=1

7 0

3 years ago

Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.

Galina-37 [17]

Question:

Prove that:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Answer:

Proved

Step-by-step explanation:

Given

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Required

Prove

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Subtract tan(10) from both sides

$- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

$tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

Factorize the right hand size

$tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)$

Rewrite as:

$tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))$

Divide both sides by $1-tan(70). tan(100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$

In trigonometry:

$tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}$

So:

$\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)}$ can be expressed as: $tan(70 + 100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$ gives

$tan(70 + 100) = -tan(10)$

$tan(170) = -tan(10)$

In trigonometry:

$tan(180 - \theta) = -tan(\theta)$

So:

$tan(180 - 10) = -tan(10)$

Because RHS = LHS

Then:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$ has been proven

6 0

3 years ago

What is 6*6? <br> and what does"*" mean?<br> the star is a asterisk but what is it for i don't know

oee [108]

Answer:

* means to multiply so 6*6 is 36

5 0

4 years ago

Which list shows fraction that ALWAYS result in a terminating decimal for values of n > 0? A) 1/11, 1/121, 1/1331 . . . , 1/1

Alla [95]

Answer:

B) 1/10, 1/100, 1/1000 . . . , 1/10n

Step-by-step explanation:

Comparing all the options given:

A) 1/11, 1/121, 1/1331 . . . , 1/11n

Finding the decimal of the first term,

1/11 = 0.0909090 (never ending decimal place)

B) 1/10, 1/100, 1/1000 . . . , 1/10n

Finding the decimal of the first term,

1/10 = 0.01 (ended decimal place)

C) 1/6, 1/36, 1/126 . . . , 1/6n

Finding the decimal of the first term,

1/6 = 0.16666667 (never ending decimal place)

D) 1/3, 1/9, 1/27 . . . , 1/3n

Finding the decimal of the first term,

1/3 = 0.33333333 (never ending decimal place)

7 0

3 years ago

Read 2 more answers

The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is its greatest possible v

julia-pushkina [17]

L= 3w

Perimeter form = 2(l+w)

2(3w + w) = 112

6w + 2w = 112
8w = 112

w= 14

The greatest possible value for w is 14

Hope this helps!

6 0

4 years ago

Read 2 more answers