-6 7/8 /(-3 3/4)
55/8X4/15
11/6
1 5/6
P = 12 + 6 + 8,5 = 18 + 8,5 = 26,5 mm
A = 12 × 4 / 2 = 48 / 2 = 24 mm²
Answer:
1) <11 and <14 are Same-Side Exterior Angles causing them to be supplementary.
2. <8 and <9 are Same-Side Interior Angles causing them to be supplementary.
Step-by-step explanation:
See answer above.
The values of the letters in coordinates (a, b) and (c,d) are;
<u><em>a = -4</em></u>
<u><em>b = -6</em></u>
<u><em>c = 2</em></u>
<u><em>d = 6</em></u>
<u><em /></u>
We are given two equations;
-6x + 3y = 6 ---(eq 1)
x² + y = 10 ---(eq 2)
- We are told that they intersect at coordinates; (a, b) and (c, d).
Let us make y the subject in eq 2 to get;
y = 10 - x² --(eq 3)
- Let us put 10 - x² into eq 1 to get;
-6x + 3(10 - x²) = 6
expanding further gives;
-6x + 30 - 3x² = 6
rearranging gives;
3x² + 6x - 24 = 0
Using online quadratic equation <em>solver</em>, we have;
x = -4 and x = 2
Putting x = -4 into eq 3 gives;
y = 10 - (-4)²
y = 10 - 16
y = -6
Putting x = 2 into eq 3 gives;
y = 10 - (2)²
y = 10 - 4
y = 6
- Thus, the coordinates are; (-4, -6) and (2, 6)
Comparing with (a, b) and (c,d), we have;
a = -4
b = -6
c = 2
d = 6
Read more at; brainly.com/question/15165519
Answer:
20*s+30*l = 280
4*s=l
Step-by-step explanation:
Let's say that the number of small boxes is s and the number of large boxes is l. Then, 20*s equals the amount of books in small boxes (as there are 20 books per small box), and 30*l for the amount of books in large boxes. Then, we know that 4 times the amount of small boxes, s, equals l, so 4*s=l. Then, as we know that the amount of books that can be held is 280, we can add the amount of books for each type of box, or 20*s+30*l, to get 280. Our equations are as follows:
20*s+30*l = 280
4*s=l
As we can define l in terms of s, making it so that we can limit the top equation to 1 variable, we can use this to determine the number of each type of box
