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bearhunter [10]

2 years ago

9

A patient is ordered 1.6 g Drug A every 8 hours over a 24

1 answer:

Vlad [161]2 years ago

5 0

Answer:

33.6 grams

Step-by-step explanation:

Rate 1;

8 hours = 1.6 g

24 hours = 24 × 1.6/8 = 4.8 hours

Rate 2;

4 hours = 1.6 g

72 hours = 72 × 1.6/4 = 28.8 g

Total grams of Drug A that the patient receive

altogether = 28.8 + 4.8 = 33.6 g

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If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)

krok68 [10]

$Tan(x-\frac{\pi }{4}) = \frac{-17}{31}$

<u>Step-by-step explanation:</u>

Here we have , sin ⁡x=7/25( given sin x = 725 which is not possible ) , $0$ . Let's find tan (x - pi/4):

⇒ $Tanx = \frac{sinx}{cosx}$

⇒ $Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}$

⇒ $Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}$

⇒ $Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}$

⇒ $Tanx = {\frac{7}{25}}(\frac{25}{24} )$

⇒ $Tanx = {\frac{7}{24}}$

Now , $Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24} -1}{1+\frac{7}{24} }$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{-17}{31}$

7 0

3 years ago

If PN=29cm and MN=13 , then PM=?

HACTEHA [7]

*see attachment for the figure referred to

Answer/Step-by-step explanation:

1. PN = 29

MN = 13

PM = ?

$PN = PM + MN$ (Segment addition postulate)

$PN - MN = PM$ (subtract MN from each side)

$29 - 13 = PM$ (substitute)

$16 = PM$

$PM = 16 cm$

2. PN = 34, MN = 19, PM = ?

$PN = PM + MN$ (sediment addition postulate)

$PN - MN = PM$ (subtract MN from each side)

$34 - 19 = PM$ (substitute)

$15 = PM$

$PM = 15 cm$

3. PM = 19, MN = 23, PN = ?

$PN = PM + MN$ (Segment addition postulate)

$PN = 19 + 23$ (substitute)

$PN = 42 cm$

4. MN = 82, PN = 105, PM = ?

$PN = PM + MN$ (segment addition postulate)

$PN - MN = PM$ (subtract MN from each side)

$105 - 82 = PM$ (substitute)

$23 = PM$

$PM = 23 cm$

5. PM = 100, MN = 100, PN = ?

$PN = PM + MN$ (Segment addition postulate)

$PN = 100 + 100$ (substitute)

$PN = 200 cm$

7 0

3 years ago

A photograph is reduced by a scale factor of 3/8 . If the original length of the photograph was 20 inches, what is the length of

Ksju [112]

To solve this problem you must apply the proccedure shown below:

1. You have that the following information given in the problem above: The<span> photograph is reduced by a scale factor of 3/8 and the original had a length of 20 inches,

2- Therefore you have:

length=20 inches-</span>(20 inches x 3/8)<span>
length=20 inches-7.5 inches
length=12.5 inches

3- Then, as you can see, the answer is: 12.5 inches.</span>

8 0

3 years ago

What is the rate of change for the following<br> function?<br> f(3)=278 and f(5)= 320.

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

22x10+h

3 0

3 years ago

MATH 20 POINTS HELP PLZ :)

lorasvet [3.4K]

Answer:

the answer is C.

Step-by-step explanation:

6 0

3 years ago