ensures that enough pressure is placed on the bearing to keep the shaft from moving around, but not so much that the bearing wil
1 answer:
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Answer:-0.4199 J/k
Explanation:
Given data
mass of nitrogen(m)=1.329 Kg
Initial pressure=120KPa
Initial temperature 300k
Final volume is half of initial
R=particular gas constant
Therefore initial volume of gas is given by
PV=mRT
V=0.986\times 10^{-3}
Using =constant
=
=337.066KPa
=
and entropy is given by
=
+
Where, =
=0.6059
=
=0.9027
Substituting values we get
=
+
=-0.4199 J/k
Answer:
ΔV =
Explanation:
Distance of earth from sun =
Spacecraft perihelion =
gravitational parameters are now given as
radius of earth = 6378 Km
Heliocentric spacecraft velocity at earth sphere of influence =
Heliocentric velocity of earth =
assume
Geometric spacecraft velocity of spacecraft at perigee of departure hyperbola
geometric space craft velocity in its circular parking orbit
ΔV =
Answer:
4.6 mm
Explanation:
Given data includes:
thin-walled pipe diameter = 100-mm =0.1 m
Temperature of pipe = -15° C = (-15 +273)K =258 K
Temperature of water = 3° C = (3 + 273)K = 276 K
Temperature of ice = 0° C = (0 +273)K =273 K
Thermal conductivity (k) from the ice table = 1.94 W/m.K ; R = 0.05
convection coefficient =2000 W/m².K
The energy balance can be expressed as:
where;
------------- equation (1)
------------ equation(2)
Equating both equation (1) and (2); we have;
Replacing the given data; we have:
r = 0.0454
The thickness (t) of the ice layer can now be calculated as:
t = (R - r)
t = (0.05 - 0.0454)
t = 0.0046 m
t = 4.6 mm