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likoan [24]
3 years ago
10

#21 is already done but 22 is so confusing Help please!

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0
(I'm not 100% sure this is accurate)

I got 4m/-4n.

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Need help with this....
Fed [463]

Answer:

m ∠S = 43°

Step-by-step explanation:

Exterior angle = Sum of opposite interior angles

(6x)° = 77° + (2x + 3)°

6x = 77 + 2x + 3

6x - 2x = 77 + 3

4x = 80

x = 20

m ∠S = (2x + 3)° = 2(20) + 3 = 40 + 3 = 43°

4 0
3 years ago
Read 2 more answers
What is the range of the following function
Shtirlitz [24]

The answer: -5 ≤ y ≤ 6

The range is all the possible output or y values of the function.

Our first point is at (1, 6) and our second point is at (-4, -5)

That means our y values are 6 and -5. Let's set up a compound inequality to represent our function.

-5 ≤ y ≤ 6. This means that x is greater than or equal to -5 and less than or equal to 6.

7 0
3 years ago
Verify cos(x+y)/cos(x-y) = cot(x-y)/cot(x+y)
JulijaS [17]

\bf \cfrac{cos(x+y)}{cos(x-y)}=\cfrac{cot(x-y)}{cot(x+y)} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{expanding the left-hand-side}}{\cfrac{cos(x)cos(y)-sin(x)sin(y)}{cos(x)cos(y)+sin(x)sin(y)}} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{expanding the right-hand-side}}{\cfrac{~~ \frac{cos(x)cos(y)+sin(x)sin(y)}{sin(x)cos(y)-cos(x)sin(y)}~~}{\frac{cos(x)cos(y)-sin(x)sin(y)}{sin(x)cos(y)+cos(x)sin(y)}}} \\\\\\ \cfrac{cos(x)cos(y)+sin(x)sin(y)}{sin(x)cos(y)-cos(x)sin(y)}\cdot \cfrac{sin(x)cos(y)+cos(x)sin(y)}{cos(x)cos(y)-sin(x)sin(y)}

3 0
3 years ago
Plz help! Actually Answer plz!
soldier1979 [14.2K]

9514 1404 393

Answer:

  time to max height: 2.5 seconds

  max height: 104 ft

  range of function: [4, 104]

Step-by-step explanation:

The equation for ballistic motion is ...

  h(t) = -16t^2 +v0·t +h0 . . . . where v0 is the initial upward speed and h0 is the initial height

For the given parameters, the height function is ...

  h(t) = -16t^2 +80t +4

The time for maximum height is ...

  -b/(2a) = -80/(2(-16)) = 2.5 . . . seconds

The maximum height is ...

  h(2.5) = (-16·2.5 +80)(2.5) +4 = 104 . . . feet

The range of the function is from the minimum height (at launch) to the maximum height:

  4 ft ≤ h(t) ≤ 104 ft.

3 0
3 years ago
If the abscissa of a point is negative , then in which all quadrants the point can lies?
Vika [28.1K]

Answer:

The point can either lie on the second quadrant or the third quadrant

Step-by-step explanation:

Mathematically, we have the ordinate and the abscissa

The ordinate represents the y axis while the abscissa represents the x axis value

For the abscissa to be negative, it means we are talking about the negative x axis

Now, the y axis can either be positive or negative too

When it is positive , we are referring to the point lying on the second quadrant

when it is negative, we are referring to the point lying on the third quadrant

8 0
3 years ago
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