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3 years ago

#21 is already done but 22 is so confusing Help please!

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

6 0

(I'm not 100% sure this is accurate)

I got 4m/-4n.

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What's the answer? help asap plssssss Please show full explanation!

AURORKA [14]

Answer:

$\huge\boxed{Answer\hookleftarrow}$

Given,

$3x - 2y = 5$

$xy = - 2$

Now,

$(3x - 2y) {}^{2} = (5) {}^{2} \\$

Use the algebraic identity ⇻ (a - b)² = a² - 2ab + b²

$(3x - 2y) {}^{2} = (5) {}^{2} \\ 3x {}^{2} - 2 \times 3x \times 2y + 2y {}^{2} = 5 {}^{2} \\ 9 {x}^{2} - 12xy + 4y {}^{2} = 25 \\9x {}^{2} + 4y {}^{2} = 25 + 12xy \\ 9x {}^{2} + 4 {y}^{2} - 1 = 24 + 12xy$

✐ So, the value of 9x² + 4y² - 1 is 24 + 12xy

Now,

xy = - 2

So, 12xy = 12 × - 2 = - 24

•°• 24 + 12xy

= 24 + (-24)

= 24 - 24

= 0

<h3>⎆ The value of 9x² + 4y² - 1 is 0.</h3>

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

4 0

3 years ago

Read 2 more answers

Tom’s total payment for his loan was $15,264. He paid it off after making 72 monthly payments.

Sveta_85 [38]

Answer:

212$ per month

Step-by-step explanation:

15,264÷72=212

5 0

3 years ago

Read 2 more answers

A scale has a percent error of 7%. The scale reads the mass of a book as 450 g.

melisa1 [442]

Answer:

The actual mass is either 453 or 447

Step-by-step explanation:

7 percent of 450

= (7/100) * 45

= 3.15

error = 3.15 g

hence actual mass

= 450 + 3.15

= 453.15

= 450 - 3.15

= 446.85

5 0

3 years ago

In a restaurant there are 3 choices for appetizers, 6 choices for entrees, and 4 choices for desserts. How many different meal c

Genrish500 [490]

Answer:

72 dessert options available

Step-by-step explanation:

3*6*4=72

6 0

4 years ago

URGENTE, POR FAVOR

Firlakuza [10]

$\mathbf A=\begin{bmatrix}a_{1,1}&a_{1,2}\\a_{2,1}&a_{2,2}\end{bmatrix}$

$a_{i,j}=2i-j\implies\mathbf A=\begin{bmatrix}2\cdot1-1&2\cdot1-2\\2\cdot2-1&2\cdot2-2\end{bmatrix}=\begin{bmatrix}1&0\\3&2\end{bmatrix}$

Por la misma razón,

$\mathbf B=\begin{bmatrix}1-1&2-1\\1-2&2-2\end{bmatrix}=\begin{bmatrix}0&1\\-1&0\end{bmatrix}$

Entonces,

$4\mathbf A=\begin{bmatrix}4\cdot1&4\cdot0\\4\cdot3&4\cdot2\end{bmatrix}=\begin{bmatrix}4&0\\12&8\end{bmatrix}$

$\mathbf A-\mathbf B=\begin{bmatrix}1&0\\3&2\end{bmatrix}-\begin{bmatrix}0&1\\-1&0\end{bmatrix}=\begin{bmatrix}1-0&0-1\\3-(-1)&2-0\end{bmatrix}=\begin{bmatrix}1&-1\\4&2\end{bmatrix}$

$\mathbf B^\top=(b_{j,i})_{2\times2}=\begin{bmatrix}b_{1,1}&b_{2,1}\\b_{1,2}&b_{2,2}\end{bmatrix}=\begin{bmatrix}0&-1\\1&0\end{bmatrix}$

Yo no reconozco la notación "Ae"... Puedes explicarla?

$a_{1,1}\cdot b_{1,1}=1\cdot0=0$

$a_{2,2}\cdot b_{1,2}=2\cdot1=2$

6 0

3 years ago