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2 years ago

Help me now !!!!! help i need help

Mathematics

1 answer:

iren2701 [21]2 years ago

4 0

cylinder:

V = πr²h

V = 3.14(2)² * 3

V = 3.14(4) * 3

V = 3.14(12)

V = 37.7m³

rectangular prism:

V = lwh

V = (2.4)(9)(5)

V = 108m³

the entirety of the sculpture:

V = volume of cylinder + volume of rectangular prism

V = 37.7 + 108

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3 years ago

Need help help on this question

balu736 [363]

Answer:70

Step-by-step explanation:

step 1:add up the angles you know

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3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

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2 years ago

a camera sells for $100. this is $10 less than twice the price of the camera last year. what was the price of the camera last ye

Lesechka [4]

Answer:

55?

Step-by-step explanation:

110 would be the last year for two and then divide by two

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3 years ago

1/2 x + 3 = 2/3 x + 1

Vladimir [108]

Answer:

x = 12

Step-by-step explanation:

4 0

3 years ago