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3 years ago

Please help! I’ll give brainliest!

Mathematics

2 answers:

ki77a [65]3 years ago

4 0

The answer is c! hope this helped!

bija089 [108]3 years ago

4 0

Answer:C

Step-by-step explanation:

tallest flower=2 1/2

Shortest flower=1 1/4

Difference=2 1/2-1 1/4

Difference=(2x2+1)/2 - (4x1+1)/4

Difference=5/2 -5/4

Difference=(10-5)/4

Difference=5/4=1 1/4

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Which set of whole numbers share the common multiples 2,520 and 3,780?

olya-2409 [2.1K]

The set of whole numbers that share the common multiples of 2,520 and 3,780 are: 35, 105, and 315.
To get these sets of whole numbers, you have to decompose 2520 and 3780 by using decomposition method or the continuous division.

See attached file.

Download docx

7 0

3 years ago

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

2 years ago

The salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation o

andrey2020 [161]

Answer:

D. 54,900

Step-by-step explanation:

We have been given that the salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation of $2,500.

To solve our given problem, we need to find the sample score using z-score formula and normal distribution table.

First of all, we will find z-score corresponding to probability $0.975(1-0.025)$ using normal distribution table.

From normal distribution table, we get z-score corresponding is $1.96$ .

Now, we will use z-score formula to find sample score as:

$z=\frac{x-\mu}{\sigma}$ , where,

$z$ = Z-score,

$z$ = Sample score,

$\mu$ = Mean,

$\sigma$ = Standard deviation

$1.96=\frac{x-50,000}{2,500}$

$1.96*2,500=\frac{x-50,000}{2,500}*2,500$

$4900=x-50,000$

$4900+50,000=x-50,000+50,000$

$54900=x$

Therefore, the salary of $54900 divides the teachers into one group that gets a raise and one that doesn't.

4 0

3 years ago

A robot can complete tasks 7 in

OLga [1]

Answer:

Step-by-step explanation:

3tasks=7/10 hours

1 task=7/(10×3)

1 task=7/30 hours

Hence a robot takes 7/30 hours to complete one task

7 0

3 years ago

USE THE ATTACHED IMAGE BELOW TO HELP DO MY HOMEWORK PLEASE<br> !!!!

BartSMP [9]

Part A

Sue

A = P*(1+r/n)^(n*t) is the compound interest formula

A = 2300*(1+0.024/1)^(1*3)

A = 2469.6061952

A = 2469.61

A - P = 2469.61-2300 = 169.61

<h3>Sue gets 169.61 pounds in interest</h3>

-----------

Bill

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*3)

A = 1989.9131472

A = 1989.91

A-P = 1989.91-1800 = 189.91

<h3>Bill earns 189.91 pounds in interest</h3>

Bill has earned more in interest.

=====================================================

Part B

By year 2, Bill has 1924.48 pounds in his account based on the work shown below

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*2)

A = 1924.4808

A = 1924.48

This amount is the new deposit, so to speak, when we change the interest rate. Now r = 0.034 changes to r = 0.04. We only go for one year so t = 1

A = P*(1+r/n)^(n*t)

A = 1924.48*(1+0.04/1)^(1*1)

A = 2001.4592

A = 2001.46

Bill has 2001.46 pounds in his account after 3 years if the interest rate for the 1234 account changes to 4% in the third year.

Now subtract off the original amount Bill deposited to get

2001.46-1800 = 201.46

For this scenario, Bill earns 201.46 pounds in interest.

Therefore, Bill has earned the most interest for both cases of the interest rate staying at 3.4% or changing to 4% for that third year.

<h3>Answer: Bill</h3>

8 0

3 years ago