2 answers:
The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm ³.
<h3>Equilibrium solubility of the compound</h3>
The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;
H₂CO3 ⇄ 2H⁺ + CO₃²⁻
x : 2x x
ksp = (2x)²x
ksp = 4x³
(1.8 x 10⁻¹⁴) = 4x³
(1.8 x 10⁻¹⁴) /4 = x³
4.5 x 10⁻¹⁵ = x³
x = (4.5 x 10⁻¹⁵)^¹/₃
x = 1.65 x 10⁻⁵ mol/dm³
Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm ³.
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The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³ .
<h3>What is solubility?</h3>
Solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.
The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;
H₂CO3 ⇄ 2H⁺ + CO₃²⁻
x : 2x x
ksp = (2x)²x
ksp = 4x³
(1.8 x 10⁻¹⁴) = 4x³
(1.8 x 10⁻¹⁴) /4 = x³
4.5 x 10⁻¹⁵ = x³
x =
x = 1.65 x 10⁻⁵ mol/dm³
Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.
Learn more about equilibrium solubility here:
brainly.com/question/23946616
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