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maksim [4K]
3 years ago
14

Can someone PLEASE help me with this im struggling bad

Chemistry
1 answer:
Art [367]3 years ago
5 0

Answer:

  1. 4.5+2.34= 6.84
  2. 4.5-5 =-0.5
  3. 6.00+3.411= 9.411
  4. 3.4×2.32 = 7.888
  5. 7.77/2.3= 3.37

7. 1200×23.4=28080

9. = 78.512

10. =341.199

11= 7.45

12 =65.0023

13.=3400210.34

Explanation:

please mark me as branliest

hope it is helpful

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Answer:

(2) Organelles must work together and their

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Explanation:

Organelles are usually located in cells. They are saddled with the role of performing specific functions in the cells for the overall functioning of life. In eukaryotic cells, the organelles are membrane bounded but in prokaryotic or primitive cells such is not the case.

Examples of cell organelles are ribosome, food vacuole, nucleus e.t.c. Just like organs in the body, organelles must work together in order to enhance life.

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3 years ago
How many moles of water are produced from 15 moles of oxygen?
Grace [21]

Answer:

30 moles

Explanation:

Water is H2O, meaning there is 2 Hydrogen atoms and 1 Oxygen atom. Oxygen is O2, because it is a diatomic molecule. (Hydrogen is also a diatomic molecule, so H2)

The equation, balanced, would have to be: 2H2 + O2 -----> 2H2O

I multiply 15 moles O2 by the molar ratio of (hydrogen/oxygen)

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Aluminum fluoride contains only aluminum and fluorine. what is the formula for this compound?
attashe74 [19]
AlF3 would be the answer
3 0
3 years ago
Read 2 more answers
When FeC13 is ignited in an atmosphere of pure oxygen, this reaction takes place. 4FeCl3(sJ 30lgJ ~ 2F~0 (sJ 6Cl2(gJ If 3.00 mol
oksano4ka [1.4K]

Answer : The reagent present in excess and remains unreacted is, O_2

Solution : Given,

Moles of FeCl_3 = 3.00 mole

Moles of O_2 = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2FeCl_3(s)+O_2(g)\rightarrow 2FeO(s)+3Cl_2(g)

From the balanced reaction we conclude that

As, 2 moles of FeCl_3 react with 1 mole of O_2

So, 3.00 moles of FeCl_3 react with \frac{3.00}{2}=1.5 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and FeCl_3 is a limiting reagent and it limits the formation of product.

Hence, the reagent present in excess and remains unreacted is, O_2

4 0
3 years ago
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