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maksim [4K]
2 years ago
14

Can someone PLEASE help me with this im struggling bad

Chemistry
1 answer:
Art [367]2 years ago
5 0

Answer:

  1. 4.5+2.34= 6.84
  2. 4.5-5 =-0.5
  3. 6.00+3.411= 9.411
  4. 3.4×2.32 = 7.888
  5. 7.77/2.3= 3.37

7. 1200×23.4=28080

9. = 78.512

10. =341.199

11= 7.45

12 =65.0023

13.=3400210.34

Explanation:

please mark me as branliest

hope it is helpful

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Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles

Now we have to calculate the moles of PbO

The balanced chemical reaction is,

2Pb(s)+O_2(g)\rightarrow 2PbO(s)

From the reaction, we conclude that

As, 2 mole of Pb react to give 2 mole of PbO

So, 2.18 mole of Pb react to give 2.18 mole of PbO

Now we have to calculate the mass of PbO

\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO

\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g

Theoretical yield of PbO = 486.1 g

Experimental yield of PbO = 367.5 g

Now we have to calculate the percent yield of the reaction.

\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100

\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%

Therefore, the percent yield of the reaction is, 75.6 %

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