6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
Answer:
No real solutions
Step-by-step explanation:
Divide both sides by 3
3x^3/3=-54/3
x^2=-18
Take square root
x=±√−18
Answer:
He has 47
Step-by-step explanation:
if one guy has 50 it wold make sense to give the other 50 but since he has 53 then he must have 47
