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Margaret [11]
4 years ago
8

If f(x)=3-|7+2x|, evaluate if f(-5)

Mathematics
2 answers:
rjkz [21]4 years ago
8 0

Answer:

0

Step-by-step explanation:

the || makes whatever number is inside it abslute so -3 becomes 3 instead

Ymorist [56]4 years ago
5 0

Answer:

f(-5)=0

Step-by-step explanation:

f(x)=3-|7+2x|\\f(-5)=3-|7+2(-5)|\\f(-5)=3-|7+(-10)|\\f(-5)=3-|-3|\\f(-5)=3-3\\f(-5)=0

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Please help :( Calculate each mountain path grade to the nearest percent.
wariber [46]
The grade of the path in the mountain is calculated by determining first the ratio between the rise over the run and multiplying the ratio by 100%. 

For Path A: 

                 grade = (rise / run) x 100%
                 grade = (1414/ 3535) x 100% = 40%

<em>Answer: 40%</em>

For Path B:
              grade = (rise / run) x 100%
              grade = (4.26 m/ 22 m) x 100% = 19.36%

Answer: 19.36%
                 
8 0
3 years ago
Plz dont answer tell pic is uploaded
avanturin [10]
√250=√(25*10)

5√10

15.8 to nearest tenth
7 0
3 years ago
A cube has a volume of 343 cubic cm. What is the area of the base
Amanda [17]

Answer:

49 cm²

Step-by-step explanation:

The volume (V) of a cube is calculated as

V = s³ ← s is the length of the side, thus

s³ = 343 ( take the cube root of both sides )

s = \sqrt[3]{343} = 7, thus

area of base = s² = 7² = 49 cm²

6 0
3 years ago
If the numerator of a fraction is increased by six, the value of the fraction will increase by one. If the denominator of the or
Alchen [17]

Answer:

\dfrac{7}{6}

Step-by-step explanation:

Let \dfrac{a}{b} be the original fraction.

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. Hence,

\dfrac{a+6}{b}=\dfrac{a}{b}+1

If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

\dfrac{a}{b+36}=\dfrac{a}{b}-1

Add these two equalities:

\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36

Substitute it into the first equation:

\dfrac{a+6}{6a-36}=\dfrac{a}{6a-36}+1\\ \\\dfrac{a+6}{6(a-6)}=\dfrac{a}{6(a-6)}+1\\ \\a+6=a+6(a-6)\\ \\a+6=a+6a-36\\ \\6a=6+36\\ \\6a=42\\ \\a=7\\ \\b=6\cdot 7-36=42-36=6

Thus, the initial fraction was

\dfrac{7}{6}

6 0
4 years ago
April is randomly choosing five CDs to bring in her car from the following: 6 pop CDs, 8 rock CDs, and 10 R
Ymorist [56]

The complement of "April choosing five Pop CDs" is "Choosing five CDs where not all of them are Pop", making the second option a right choice.

In the question, we are given that April is randomly choosing five CDs to bring in her car from the following: 6 Pop CDs, 8 Rock CDs, and 10 R&B CDs.

We are asked what will be the complement of April choosing 5 Pop CDs.

The complement of a set is the one, where no element of the original set is present.

The original set is that "April is choosing 5 Pop CDs".

This means that April, while choosing 5 CDs from the given set, chooses all 5 CDs to be Pop.

While making the complement we need to change the final outcome.

To change this, we just need to make one exception to this, which can be achieved by making one other than Pop CD.

This gives us the set: "Choosing 5 CDs where not all of them are complement".

Thus, the complement of "April choosing five Pop CDs" is "Choosing five CDs where not all of them are Pop", making the second option a right choice.

Learn more about the complement of an event at

brainly.com/question/3728788

#SPJ4

The given question is incomplete. The complete question is:

"April is randomly choosing five CDs to bring in her car from the following: 6 pop CDs, 8 rock CDs, and 10 R&B CDs. What is the complement of April choosing five pop CDs?

choosing five CDs where none of them are pop

choosing five CDs where not all of them are pop

choosing five CDs where at least one of them is pop

choosing five CDs where all of them are pop"

7 0
2 years ago
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