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Vlad [161]
3 years ago
9

The area of a square quilt is 196 square inches. There is a smaller square patch on the quilt with an area of 49 square inches.

What is the difference between the overall perimeter of the quilt and the perimeter of the smaller square patch?
Mathematics
2 answers:
Makovka662 [10]3 years ago
5 0




To find your answer you would find the perimeter of the small square which is 28.

You would then find the perimeter of the big square which is 56. 

Next, you subtract 56 from 28 and get 28.  

So the difference is 28 inches.

Hope this helps!!



worty [1.4K]3 years ago
4 0
First find the length of one side of the quilt and patch. In this case you just need to calculate square roots of 196 and 49. 
So the length of one side of the quilt is: √196=14.
The length of one side of the patch is: √49=7.
Last step is to find the difference of perimeter of quilt and the patch: 14×4-7×4=28.
So, here we go, your final answer for this problem should be 28!
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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
What is the slope of the following linear equation y + 2x = 5 ?
Arte-miy333 [17]

Answer:

slope = -2

Step-by-step explanation:

The general structure of an equation in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. Since the given equation is not in the exact slope-intercept form, we need to rearrange it to identify the slope.

y + 2x = 5                         <----- Given equation

y = -2x + 5                       <----- Subtract 2x from both sides

Now, we can see that in the "m" position, there is a value of -2. This makes the slope = -2.

4 0
2 years ago
HELP ASAP HELP PLEASE ASAP
Gnesinka [82]

Answer:

WXYZ can not be a rectangle because consecutive sides are not perpendicular to each other.

Step-by-step explanation:

The given vertices are W(-4,3), X(1,5), Y(3,1) and Z(-2,-1).

Plot these points on coordinate plane and draw the quadrilateral as shown below.

Slope=\dfrac{y_2-y_1}{x_2-x_1}

Using this formula, we get

m_{WX}=\dfrac{5-3}{1-(-4)}=\dfrac{2}{5}

m_{XY}=\dfrac{1-5}{3-1}=\dfrac{-4}{2}=-2

Now,

m_{WX}\times =\dfrac{2}{5}\times (-2)=-\dfrac{4}{5}\neq -1

Here, WX and XY are two consecutive sides of quadrilateral but the product of their slopes is not equal to -1. It means they are not perpendicular to each other.

Since, all interior angles of a rectangle are right angles, therefore, WXYZ can not be a rectangle.

5 0
2 years ago
5x - 4y = 0 in point intercept form
Contact [7]

Answer:

in slope-intercept form y = 5/4x in y-intercept form is b = 0. try to use math___way dot com

Step-by-step explanation:

6 0
3 years ago
I honestly don't even know where to start //// on his last 4 tests , Danilo scored 55% 78% 84% and 93%. What score should he get
skelet666 [1.2K]

Answer:

The answer to your question is He must get 80%

Step-by-step explanation:

Data

Scores 55%, 78%, 84%, 93% and X

Average 80%

Process

1.- Write a equation to solve this problem

- There are five scores

Score 1 = S1 = 55

Score 2 = S2 =  78

Score 3 = S3 = 84

Score 4 = S4 = 93

Score 5 = S5 = X

Equation

               Average = (S1 + S2 + S3 + S4 + S5) / 5

- Solve for S5

               5 Average = S1 + S2 + S3 + S4 + S5

               S5 = 5 Average - S1 - S2 - S3 - S4

- Substitution

               S5 = 5(80) - 55 - 78 - 84 - 93

- Simplification

               S5 = 400 - 310

- Result

               S5 = 90

5 0
3 years ago
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