In the year 2008, a person bought a new car for $23500. For each consecutive year after that, the value of the car depreciated b
y 10%. How much would the car be worth in the year 2011, to the nearest hundred dollars?
1 answer:
Answer:
$17131.50
Step-by-step explanation:
23500 decrease 10% =
23500 × (1 - 10%) = 23500 × (1 - 0.1) = 21150
21150 decrease 10% =
21150 × (1 - 10%) = 21150 × (1 - 0.1) = 19035
19035 decrease 10% =
19035 × (1 - 10%) = 19035 × (1 - 0.1) = 17131.5
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