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Nostrana [21]
2 years ago
15

How many quarts of pure antifreeze must be added to 2 quarts of a 20% antifreeze solution to obtain a 60% antifreeze solution?

Mathematics
1 answer:
blsea [12.9K]2 years ago
4 0

The quantity of pure antifreeze that must be added to 2 quarts of a 20% antifreeze solution to obtain a 60% antifreeze solution 2 quarts

How to solve equation?

  • x = quarts of 100% antifreeze

You have 2 quarts of 20% antifreeze.

(100%)x + (20%)2 = 60%(x + 2)

100x + 40 = 60(x + 2)

100x + 40 = 60x + 120

100x - 60x = 120 - 40

40x = 80

x = 80/40

x = 2 quarts

Learn more about equation:

brainly.com/question/1214333

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A lawn mower cost $470 when new and is expected to last 10 years. What will it be worth in 7.5 years? (Assume the lawn mower has
USPshnik [31]
Answer: 117.5
Explanation: Assuming that after 10 years the lawn mower would have a value of 0. We can evenly divide $470 by the amount of years.
$750/10 = $75
We would then multiply 75*7.5 years to then realize the value lost over that amount of time would be $352.5, subtracting that from the original value of $470 would then be 117.5
5 0
2 years ago
Jana And Jordan had 23 oranges Jana had 7 fewer oranges than Jordan how many oranges did each girl have
Solnce55 [7]

Answer:

Jana had 8 oranges, and Jordan had 15 oranges.

Step-by-step explanation:

First, identify what you know:

1) In total, Jana and Jordan had 23 oranges.

2) Jana had 7 less oranges than Jordan.

We can create a formula, where x equals the number of oranges Jana has.

23 = x + (x + 7)

16 = x + x (subtracted 7 from both sides)

x = 8 (divided both sides by 2)

So, now we know Jana had 8 oranges, which is 7 less than Jordan.

8 + 7 = ?

? = 15

Jana had 8 oranges, while Jordan had 15, for a total of 23 oranges.

3 0
3 years ago
Find the distance d from (6.1, 5.9) to (-5.9, -4.1) .
photoshop1234 [79]
Distance formula:
√(x1-x2)^2+(y1-y2)^2

4 0
2 years ago
Mark is 4 year older than 2 times his sister Helena's Age. Let h represent Helena's age and m represent Mark's age. Write an equ
andreyandreev [35.5K]
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7 0
3 years ago
Can someone please give me the (Answers) to this? ... please ...<br><br> I need help….
bezimeni [28]

Answer:

see explanation

Step-by-step explanation:

2 chords intersecting inside a circle , then the product of the parts of one chord is equal to the product of the parts of the other chord.

6

BE × ED = AE × CE , that is

10 × 3x = 12(2x + 1) ← distribute parenthesis by 12

30x = 24x + 12 ( subtract 24x from both sides )

6x = 12 ( divide both sides by 6 )

x = 2

then

ED = 3X = 3(2) = 6

7

RJ × JP = SJ × JQ , that is

6 × 3x = 4(4x + 1) ← distribute parenthesis by 4

18x = 16x + 4 ( subtract 16x from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

then

RP = RJ + JP = 6 + 3x = 6 + 3(2) = 6 + 6 = 12

6 0
1 year ago
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