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3 years ago

What is the square feet of 71inces x 36inches?

1 answer:

3 0

71 inches X 36 inches = 2556 sq inches

convert sq.feet to sq.inches.

12 sq. feet = 1 sq. inch

2556 sq. feet × 1 sq. inch ÷ 12 sq. feet = 213 sq. inches (sq. feet ÷ sq. feet cancels out the feet variable leaving sq. inch)

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Sarah's class went to the science lab for their weekly lab activity. Sarah's group decided that they could complete the lab fast

saw5 [17]

Answer:

To not mess things up. i think

5 0

3 years ago

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Sandra saves 7% of her salary for retirement. This year her salary was $2,000 more than her salary than in the previous year, an

Effectus [21]

9514 1404 393

Answer:

2,000
$45,000

Step-by-step explanation:

Where x represents the previous year's salary, its amount this year is said to be ...

x + 2000

The equation is trying to reflect the fact that 7% of that is $3,290. The missing number is 2000:

0.07(x +2000) = 3290

Solving for x, we find ...

x = (3290/0.07) -2000 = 45000

Sandra's salary the previous year was $45,000.

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3 years ago

I need help ASAP?!!!!!!

Elodia [21]

Answer:

x = 2

Step-by-step explanation:

5x - 6 = 4

add 6 to each side

5x = 10

divide each side by 5

x = 2

3 0

3 years ago

Add. 34.700 + 98.428 98.775 132.435 132.980 133.128

lesantik [10]

Answer:

34.700+98.42+98.775+132.435+132.980+133.128

5 0

2 years ago

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Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago