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jasenka [17]
3 years ago
15

4, 13, 22, ... Find the 35th term.

Mathematics
2 answers:
Inessa [10]3 years ago
8 0

Answer:

im thinking its 40.. tho im not sure im pretty sure it is so im sorry if its wrong

Step-by-step explanation:

Mice21 [21]3 years ago
5 0

Answer:

310

Step-by-step explanation:

1.Find your constant difference of the sequence by subtracting from left to right which is 9

2. find your fomula by using Tn=bn+C (b is your constant difference you can find C by C=T1 -b ) which will then give us 9n-5

3. T(35)=9n-5=9(35)-5=310

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George earned $50
abruzzese [7]
Well he earned $50 this week and $25 the following week, so 2/5 of $75 is $30
5 0
3 years ago
Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are rando
qwelly [4]

Answer: The probability that both televisions work is 0.5625 .

The probability at least one of the two televisions does not​ work is 0.4375.

Step-by-step explanation:

Given : Number of televisions received in shipment= 12

Number of defective televisions received in shipment= 3

Then proportion of defective televisions =\dfrac{3}{12}=0.25

Using binomial probability formula, the probability of getting success in x trials is given by :-

P(x)=^nC_xp^x(1-p)^{n-x}

If two televisions are randomly​ selected, then the probability that both televisions work will be :-

P(0)=^2C_0(0.25)^0(0.75)^2=(0.75)^2=0.5625

The probability at least one of the two televisions does not​ work will be :-

P(x\geq1)=1-P(0)=1-0.5625=0.4375

6 0
3 years ago
In answering a question on a multiple-choice test, a student either knows the correct answer or guesses it. Let 0.7 be the proba
Dahasolnce [82]

Answer:

The probability is 0.9211

Step-by-step explanation:

Let's call K the event that the student know the answer, G the event that the student guess the answer and C the event that the answer is correct.

So, the probability P(K/C) that a student knows the answer to a question, given that she answered it correctly is:

P(K/C)=P(K∩C)/P(C)

Where P(C) = P(K∩C) + P(G∩C)

Then, the probability P(K∩C) that the student know the answer and it is correct is:

P(K∩C) = 0.7

On the other hand, the probability P(G∩C) that the student guess the answer and it is correct is:

P(G∩C) = 0.3*0.2 = 0.06

Because, 0.3 is the probability that the student guess the answer and 0.2 is the probability that the answer is correct given that the student guess the answer.

Therefore, The probability P(C) that the answer is correct is:

P(C) = 0.7 + 0.06 = 0.76

Finally, P(K/C) is:

P(K/C) = 0.7/0.76 = 0.9211

7 0
3 years ago
Anyone know how to work this out?
dsp73
The first and crucial thing we want to take notice is that the lines DF and EG intersect at point H which creates 4 different triangles in the rhombus. The innermost angles of DGH and EFH are vertical angles and vertical angles are congruent. So if the angles of the triangles are congruent than the triangles themselves are congruent. This is supported by the vertical angles theorem.
4 0
3 years ago
Read 2 more answers
What is the formula for a confidence interval?
ikadub [295]

Answer:

a) The formula is given by mean \pm the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

b) \bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

If the distribution for X is normal or if the sample size is large enough we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Part a

The formula is given by mean \pm the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

Part b

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

5 0
4 years ago
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