Hey there,
I believe that your correct answer would be that "<span> some people will tell you what they think you want to hear </span>". When you ask someone about the perceptions of your person trait, they will most likely <span>tell you what they think you want to hear because its what they want to make you happy.
For example: Jimmy ask billy "Am I fat Billy"
Billy tells Jimmy "No, Your not fat, you look just great".
But really, Jimmy is very fat.
The point is that people are going to say things that make you feel happy and something that you want to hear.
~Jurgen</span>
<span>A switch is a central network device that connects network nodes such as workstations and servers in a physical Star topology</span>
Answer:
D
Explanation:
Search engine optimization (SEO)
Answer:
A. The song was saved using fewer bits per second than the original song.
Explanation:
A song can be recorded on the computer or any device ranging from bit rates 96 kbps to 320 kbps.
The lesser the bitrates the lesser the quality of the audio and when we increase the bit rates, the quality of the audio recorded gradually increases.
Bitrates of 128 kbps give us a radio like quality whereas when we use bitrates of 320 kbps we get very good or CD-like quality.
According to the scenario, the most appropriate answer is option A.
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
