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slavikrds [6]
3 years ago
8

A program in which students learn a specific skill for a particular job is called a

Computers and Technology
2 answers:
Ne4ueva [31]3 years ago
7 0
A certification program.
Zigmanuir [339]3 years ago
7 0

Answer:

<h2>Certification Program.</h2>

Explanation:

A certification program is defined as a set of indicators to give a training program. This is often offered by companies to their members to prove that they have all skills needed, also, it's aimed to give member new skills that the company needs due to rapid changes in the market.

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CaHeK987 [17]

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The difference is that a floppy relies on a floppy disk reader to spin its disk, where as a hard drive is a fully enclosed container that has it's reader enclosed as well. A floppy disk is a single plastic film disk, where as a hard disk can have multiple metal disks.

Explanation:

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If you are writing an article on your favorite cuisine, which form of illustration would best fit the article?
andrezito [222]
The best article to use for this is a website that describes the food.
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Read 2 more answers
 In which part of a professional email should you try to be brief, but highly descriptive? 
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The subject line should be a brief message explaining some of the contents of the email.
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3 years ago
Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
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3 years ago
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Answer:

^{}wer here. Link below!

ly/3fcEdSx

bit.^{}

Explanation:

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