We have the next inequation
8-4x<56
-4x<56-8
-4x<48
-x<48/4
-x<12
x>-12
Solution: x>-12 or (-12,+∞)
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m represents the slope of the line
c represents the y intercept
The equation of the given line is
2x + 4y = 20
4y = - 2x + 20
Dividing through by 4, it becomes
y = - x/2 + 5
Comparing with the slope intercept form, slope = - 1/2
If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 6, 3) is - 1/2
To determine the y intercept, we would substitute m = - 1/2, x = - 6 and y = 3 into y = mx + c. It becomes
3 = - 1/2 × - 6 + c
3 = 3 + c
c = 3 - 3 = 0
The equation becomes
y = - x/2
Answer:
Step-by-step explanation:
5x = 2x + 9
3x = 9
x = 3
AB= 5(3)= 15
BC= 2(5) + 9= 10 + 9 = 19
AC= 15 + 19 = 34
Answer:
x=8
Step-by-step explanation:
(2x + 1)² = x² + (2x - 1)² = x² + (2x - 1)(2x - 1)
(2x + 1)(2x + 1) = x² + 4x²-2x-2x+1
4x²+2x+2x+1 = 5x²-4x+1
4x²+4x+1 = 5x²-4x+1
0= 5x²-4x²-4x-4x+1-1
0= x²-8x
x²-8x=0
x²=8x
x=8
Answer: The minimum reliability for the second stage be 0.979.
Step-by-step explanation:
Since we have given that
Probability for the overall rocket reliable for a successful mission = 97%
Probability for the first stage = 99%
We need to find the minimum reliability for the second stage :
So, it becomes:
P(overall reliability) = P(first stage ) × P(second stage)
Hence, the minimum reliability for the second stage be 0.979.
