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asambeis [7]
2 years ago
5

6u + 2u + 3 help meeee

Mathematics
1 answer:
svlad2 [7]2 years ago
3 0

Answer:

8u + 3

Step-by-step explanation:

the 6u and 2u are like terms, so they can be added. the 3 must stay on its own though, as it does not have a u in front of it:)

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Please help with this question!!
DIA [1.3K]

Answer:

x = 8 and y = 18, and the scale factor is 3/2

Step-by-step explanation:

Because we have two complete pairs in the similar trapezoids, we can find the scale factor as 3/2, or 36/24 or 24/16.

To find the missing values of x and y, we just make the equations to get 3x/2 = 12 and 12 * 3/2 = y. This means x = 8 and y = 18.

6 0
3 years ago
What is the length of segment TU?
matrenka [14]
QR=RS+QS

UT cuts QR and QS in half equally.

that means that UT is equal to half of RS <span />
4 0
3 years ago
As you leave​ Clark, the sign says Lutherville 145 ​miles, Otisburg 195 miles. If the Planet Diner is halfway between Luthervill
Rasek [7]

Answer:

Therefore Planet Diner is located 170 miles from Clark.

Step-by-step explanation:

We are given our origin, which is Clark (C) and three Locations as Lutherville (L), Otisburg (O) and Planet Diner (PD).

We know that the distance between Clark and Lutherville is 145 miles.

We know that the distance between Clark and Otisburg is 195 miles.

We also know that Planet Diner is halfway between Lutherville and Otisburg, thus exactly in between them.

<em><u>So if we can find the position of Planet Diner between Lutherville and Otisburg,  we will automatically know its distance from Clark, since Clark is the reference origin for ALL locations. </u></em>

Thus we have

PD=\frac{L+O}{2}

PD=\frac{195+145}{2}

PD=\frac{340}{2}

PD=170

Therefore Planet Diner is located 170 miles from Clark.

3 0
3 years ago
What value would have to be added to both expressions in order to solve by completing the square?
kati45 [8]

Answer:

29

Step-by-step explanation:

4 0
4 years ago
At 2:00pm a car's speedometer reads 20mph, and at 2:10pm it reads 30mph.
Dmitry [639]

Over this 10-minute interval, the car's average acceleration is

\dfrac{30\,\mathrm{mph}-20\,\mathrm{mph}}{10\,\mathrm{min}}=\dfrac{10\,\mathrm{mph}}{\frac16\,\mathrm h}=60\dfrac{\rm mi}{\mathrm h^2}

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.

6 0
4 years ago
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