33.3% sugar
you do 5÷15 (part÷whole)
Answer:
The triangle angle rule says that all of the angles in a triangle will add up to equal 180. So to find x we subtract the given angles ( 45 and 60 in this case) from 180.
x = 180-60-45
180-60-45=75
so x = 75
To find y we know that angle x and and y are angles formed on a straight line that are split up by a triangle segment. These angles are called supplementary angles which add up to equal 180.
So knowing that angle x = 75 we can find angle y by subtracting 75 from 180
180-75=105 so y = 105
Another way we could solve for y is the exterior triangle rule
This rule states that an exterior angle of a triangle is equal to the two opposite interior angles
so y = 45 + 65
45 + 65=105
so y = 105
Step-by-step explanation:
Answer:
2.16
Step-by-step explanation:
The question is on mean absolute deviation
The general formula ,
Mean deviation = sum║x-μ║/N where x is the each individual value, μ is the mean and N is number of values
<u>Team 1</u>
Finding the mean ;

Points Absolute Deviation from mean
51 2
47 2
35 14
48 1
64 15
<u>Sum </u> 34
Absolute mean deviation = 34/5= 6.8
<u>Team 2</u>
Finding the mean

Points Absolute deviation from the mean
27 15.8
55 12.2
53 10.2
38 4.8
41 1.8
<u>Sum 44.8 </u>
Absolute deviation from the mean = 44.8/5 =8.96
Solution
Difference in mean absolute deviation of the two teams = 8.96-6.8 = 2.16
Answer:
C = (2, 6)
Step-by-step explanation:
The coordinates of point C can be found as the weighted average of the endpoint coordinates. The weights are the reverse of the relative segment lengths.
For AC : CB = 3 : 1, we have ...
C = (A +3B)/(1+3) = ((-1, 0) +3(3, 8))/4 = (-1+9, 0+24)/4
C = (2, 6)
Answer:
71
Step-by-step explanation:
This is the answer because:
1) First, add Andy's score and Janet's score in order to know how much they got in total:
- Janet's score: 119 + 96 + 145 = 360
- Andy's score: 127 + 74 + 88 = 289
2) In order to find how much more Janet scored, jus subtract Andy's score from Janet's score:
Therefore, the answer is 71.
Hope this helps! :)