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3 years ago

If f(x)=4(3x-5), find f^-1(x)

Mathematics

1 answer:

Margaret [11]3 years ago

3 0

Answer:

f^-1(x) = (x+20) / 12

Step-by-step explanation:

f(x) = 4(3x-5)

Let y be the image of f.

y = 4(3x-5)

y = 12x-20

y+20 = 12x

x = (y+20) / 12

f^-1(y) = (y+20) / 12, so

f^-1(x) = (x+20) / 12

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♡Complete the equation of this circle:

Lady_Fox [76]

The equation of the given circle is :

$(x - 2) {}^{2} + (y - ( - 2)) {}^{2} = 9$

So the value in the blanks will be :

1st = 2

2nd = -2

3rd = 9

6 0

3 years ago

Evaluate each expression if a= 12, b =9, c= -4 (a2/4b)+c

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Here it issssss #studywell

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3 years ago

A line that includes the point (0, -2) has a slope of -3. What is its equation in slope-intercept form?

denpristay [2]

Answer:

$y=-3x-2$

Step-by-step explanation:

Equation of straight line in slope intercept form is given as

$y=mx+b$ -------- (1)

Here $m=-3$ and $(x_1, y_1)=(0, -2)$

$y-y_1 = m(x-x_1) \\ y+2 = - 3(x-0) \\ y =-3x-2$ ----------- (2)

Comparing (1) and (2)

m=-3 and b=-2

Equation (2) is equation of straight line with slope -3 and y-intercept -2 in slope intercept form

5 0

3 years ago

What is the diameter of circle T?

Ratling [72]

Answer:

$Diameter = 16$

Step-by-step explanation:

Given

$\theta = 72$

$Sector = \frac{64}{5}\pi$

Required

Calculate the diameter

The area of a sector is:

$Area = \frac{\theta}{360} * \pi r^2$

Substitute values for Area and $\theta$

$\frac{64}{5}\pi = \frac{72}{360} * \pi r^2$

Divide both sides by $\pi$

$\frac{64}{5} = \frac{72}{360} * r^2$

Make $r^2$ the subject

$\frac{64*360}{5*72} = r^2$

$\frac{64*360}{360} = r^2$

$64 = r^2$

Take positive square roots of both sides

$\sqrt{64} = r$

$8 = r$

$r = 8$

The diameter is then calculated as:

$Diameter = 2r$

$Diameter = 2*8$

$Diameter = 16$

5 0

3 years ago

The endpoints of line GH are G(0,4) and H(-6,2). find the coordinates of the midpoint M

PtichkaEL [24]

Answer: The point G is G(18,-9)

Step-by-step explanation:

Midpoint:

Write the formula for midpoint of the A(x_1,y_1) and B(x_2,y_2).

[(x_1+x_2)/2,(y_1+y_2)/2]

G(x,y), H(-2,9)

(8,0) =[(x+(-2))/2,(y+9)/2]

(x+(-2))/2 =8

(x+(-2))=16

x-2 =16

x =18

(y+9)/2=0

y+9=0

y=-9

The point G is G(18,-9)

(answer found from user homeworkhelp on mathskey.com)

4 0

3 years ago