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3 years ago

2. Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?

Mathematics

1 answer:

Maksim231197 [3]3 years ago

7 0

Explanation:

The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.

More formally, if V is the common vertex, and ...

R is a point on one of the rays forming Angle 1
S is a point on the ray that is the opposite of ray VR
T is a point on the other ray forming Angle 1
U is a point on the ray that is the opposite of ray VT

Then angle RVT and angle SVU are vertical angles.

___

Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.

If the above conditions cannot be met, then the angles are not vertical angles.

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F(x) = 4x^2+2x+6 what is the discriminant of f? How many distinct real number zeros does f have?

Sunny_sXe [5.5K]

Answer:

The discriminant of f is 92, and it has no real zeros

Step-by-step explanation:

The discriminant of a quadratic is $b^2-4ac$ , where the quadratic is in the form $ax^2+bx+c$ . The discriminant of this one is therefore:

$2^2-4(4)(6)=4-96=-92$

Since the square root of a negative number is imaginary, this quadratic has no real number zeros. Hope this helps!

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2 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

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2 years ago

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Elis [28]

Answer:

The negative effects of a recession would be reduced by which fiscal policy decision?

A. incurring a budget deficit which is used to retire debt held by the public

<h3>B. incurring a budget surplus and allowing that surplus to accumulate as idle Treasury balances</h3>

C. incurring a budget surplus, which is used to retire debt held by commercial banks

D. incurring a budget deficit by borrowing from the public and increasing expenditures

Step-by-step explanation:

#CarryOnLearning

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3 years ago

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Kazeer [188]

Answer:

C

Explanation:

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valina [46]

Slope is rise/run
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