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bulgar [2K]
1 year ago
12

Suppose y varies inversely as x, and y = 16 when x = 1/2. Find y when x = 17.

Mathematics
1 answer:
MArishka [77]1 year ago
5 0

<u>Finding the proportionality constant</u> :

  • y = k/x
  • 16 = k/(1/2)
  • <u>k = 8</u>

<u>Finding y when x = 17</u> :

  • y = 8/(17)
  • y = 8/17

The value of y is <u>8/17</u> when x = 17.

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Give examples of two substances that look similar, but have different properties.
gogolik [260]

Answer:

Water and alcohol

Step-by-step explanation:

They are both a clear liquid. However, their properties are very different. Here are a few of the things that set them apart.

  • their smell
  • their PH
  • their density
8 0
3 years ago
PLEASE HELP I’LL GIVE BRAINLIST.
kolezko [41]

Answer:

2/6 is probably your answer

Step-by-step explanation:

5 0
3 years ago
A cube is intersected by a plane from the top edge of one face to the bottom edge of the opposite face as shown.
Alexandra [31]

Answer:

B

Step-by-step explanation:

a rectangle that is not a square

5 0
3 years ago
Plot of land between two roads are laid out according to the boundaries shown. The boundaries between the two roads are parallel
FinnZ [79.3K]
Given: 
                Cheshire Road           Shelby Road
Plot 1           40 yards                       48 yards
Plot 3                x                                56 yards


To solve for x, we get the ratio and proportion of both plots.

40/48 = x/56

Do cross multiplication.

40 * 56 = 48 * x
2,240 = 48x
2,240/48 = 48x/48
46.67 = x

Plot 3 of Chesire Road measures 46.67 or 46 2/3 yards.  Choice A. 


5 0
3 years ago
Read 2 more answers
The function g(x) = 12,500(0.91)x represents the value of a piece of farm equipment after x years. Approximately when will its v
topjm [15]

Answer:

B. 7.3 years

Step-by-step explanation:

The question is wrong. The correct function is :

g(x)=12500(0.91)^{x}

We have the function g(x) that represents the value of a piece of farm equipment after x years.

This means that when x=0 its original value is :

g(0)=12500(0.91)^{0}=12500

Now we want to calculate approximately when will its value be half its original value. Then, we write :

\frac{12500}{2}=6250

6250 is half of its original value. We need to find x that satisfies the following equation :

g(x)=6250=12500(0.91)^{x}

Solving for x :

6250=12500(0.91)^{x} ⇒

0.5=(0.91)^{x}

Now we apply natural logarithm to each side of the equation :

ln(0.5)=ln[(0.91)^{x}]

Using logarithm properties :

ln(0.5)=ln[(0.91)^{x}] ⇒

ln(0.5)=x[ln(0.91)]

x=\frac{ln(0.5)}{ln(0.91)} ⇒

x ≅ 7.3496

The correct option is B. 7.3 years

4 0
3 years ago
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