Equation fo a circle:
Data:
Center: C(x₀,y₀).
radius: r
(x-x₀)²+(y-y₀)²=r²
In this equation:
(x+4)²+(y-6)²=25
C(-4,6)
r²=25 ⇒r=√25=5
Then, it´s radius is 5.
If, we have got two points:
A(x₁,y₁)
B(x₂,y₂)
The distance beetween the points is:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²]
Then:
A(-6,7)
B(-1,-5)
dist(A,B)=√[(-1+6)²+(-5-7)²]
dist (A,B)=√(5²+12²)
dist (A,B)=√(25+144)
dist (A,B)=√169
dist (A,B)=13
the distance between the points (-6,7) and (-1,-5) is 13.
<span> broker p will charge 184.38 less than broker q</span>
Step-by-step explanation:
hopefully this helps:)
Answer:
Step-by-step explanation:
Remember that TR is 1/3 the length of MR
MR = 54
TR = 1/3 *MR
TR = 1/3 * 54
TR = 18
Answer:
"minimum value = 0; maximum value = 8"
Step-by-step explanation:
This is the absolute value function, which returns a positive value for any numbers (positive or negative).
For example,
| -9 | = 9
| 9 | = 9
| 0 | = 0
Now, the domain is from -8 to 7 and we want to find max and min value that we can get from this function.
If we look closely, putting 7 into x won't give us max value as putting -8 would do, because:
|7| = 7
|-8| = 8
So, putting -8 would give us max value of 8 for the function.
Now, we can't get any min values that are negative, because the function doesn't return any negative values. So the lowest value would definitely be 0!
|0| = 0
and
ex: |-2| = 2 (bigger), |-5| = 5 (even bigger).
So,
Min Value = 0
Max Value = 8
