Answer:
A. 5
B. 6
I hope this is helpful for you! Unless my calculator is wrong!
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Answer:
20cos(39) or 15.543 (3 d.p.)
Step-by-step explanation:
- Use SOHCAHTOA
- You want to find A and have an angle of 36° and H
- So use CAH
- cos(39) = x / 20
- x = 20cos(39)
To find the volume of the computer, we just have to multiply each coordinate.

<h2>Hence, the volume is 32.4 cubic inches.</h2>
Answer:
the answer is A 90+0.25x=147.50
Step-by-step explanation:
if this is useful please make me brainliest