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harina [27]
2 years ago
15

What did the cheesy Elvis sing about?

Mathematics
2 answers:
Nady [450]2 years ago
8 0

Answer:

do you mean Elvis Presley if so he wasn't cheesy he was a great musician with great movies don't talk bad about the king of rock n roll.

Step-by-step explanation:

chubhunter [2.5K]2 years ago
6 0

Answer:

i dont know

Step-by-step explanation:

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Write a two-step equation that involves multiplication and subtraction, includes a negative coefficient , and has a solution of
Allisa [31]

Answer:

-60x+20 = -400

x equals 7

Step-by-step explanation:

3 0
2 years ago
The cost of 12 kg sugar is $240 what will be the cost of 3 kg sugar​
Alexus [3.1K]

Question:

The cost of 12 kg sugar is $240 what will be the cost of 3 kg sugar.

Given:

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To find?

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Answer :

<u>To find </u><u>c</u><u>o</u><u>s</u><u>t</u><u> </u><u>of</u><u> </u><u>3kg sugar first we have to find cost of 1 kg sugar</u><u>.</u>

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<u>Now Let's find cost of 3 kg sugar</u>

Cost of 3kg sugar = total no of sugar ×Cost of 1 kg sugar

Cost of 3kg sugar = 3×$20

Cost of 3kg sugar = $60

3 0
2 years ago
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^5(+3)^0\\&#10;2&+5&(2x)^4(+3)^1\\&#10;3&+10&(2x)^3(+3)^2\\&#10;4&+10&(2x)^2(+3)^3\\&#10;5&+5&(2x)^1(+3)^4\\&#10;6&+1&(2x)^0(+3)^5&#10;\end{array}

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for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^4(-3y)^0\\&#10;2&+4&(2x)^3(-3y)^1\\&#10;3&+6&(2x)^2(-3y)^2\\&#10;4&+4&(2x)^1(-3y)^3\\&#10;5&+1&(2x)^0(-3y)^4&#10;\end{array}


\bf (3a+4b)^8\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(3a)^8(+4b)^0\\&#10;2&+8&(3a)^7(+4b)^1\\&#10;3&+28&(3a)^6(+4b)^2\\&#10;4&+56&(3a)^5(+4b)^3\\&#10;5&+70&(3a)^4(+4b)^4\\&#10;6&+56&(3a)^3(+4b)^5\\&#10;7&+28&(3a)^2(+4b)^6\\&#10;8&+8&(3a)^1(+4b)^7\\&#10;9&+1&(3a)^0(+4b)^8&#10;\end{array}

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7 0
3 years ago
Read 2 more answers
What are all that apply?​
Nostrana [21]

height or altitude for a parallelogram means the perpendicular distance from one parallel side to the other.  Check the picture below.

7 0
2 years ago
A group consists of fivefive men and sevenseven women. FourFour people are selected to attend a conference.
exis [7]

Answer:

Step-by-step explanation:

a.

4 people can be selected in ways=12 P4=12×11×10×9=11880

b.

4 women can be selected in  ways=7P4=7×6×5×4=840

c.

P=\frac{840}{11880} =\frac{7}{99}

6 0
3 years ago
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