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2 years ago

If a=x+y and b=x-y ,show that (a-b)^2=4y^2

Mathematics

1 answer:

NemiM [27]2 years ago

7 0

Step-by-step explanation:

$((x + y) - (x - y) ){}^{2} = 4 {y}^{2}$

$(2y) {}^{2} = 4 {y}^{2}$

${2}^{2} {y}^{2} = {4y}^{2}$

$4 {y}^{2} = 4 {y}^{2}$

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We can rewrite the given time as:

7.03x10^15 mins
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<h3>What is 4.22x10^17 seconds in minutes and hours?</h3>

First, remember that:

60s = 1 min

Then to write that amount in minutes, we just need to divide by 60, so we get:

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Similarly, you can change to any time unit that you want, for example:

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The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of

Effectus [21]

Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = <u><em>the blood platelet counts of a group of women</em></u>

So, X ~ Normal( $\mu=257.62, \sigma^{2} =62.1^{2}$ )

Now, the empirical rule states that;

68% of the data values lie within the 1 standard deviation of the mean.

95% of the data values lie within the 2 standard deviations of the mean.

99.7% of the data values lie within the 3 standard deviations of the mean.

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

z-score of 443.9 = $\frac{X-\mu}{\sigma}$

= $\frac{443.9-257.62}{62.1}$ = 3

z-score of 71.3 = $\frac{X-\mu}{\sigma}$

= $\frac{71.3-257.62}{62.1}$ = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

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3 years ago

If a=x+y and b=x-y ,show that (a-b)^2=4y^2​

If a=x+y and b=x-y ,show that (a-b)^2=4y^2