What is the slope of the line that passes through the points (5,6) and (5,9)?
1 answer:
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Answer:
CD ≈ 26.0 cm
Step-by-step explanation:
using the sine ratio in right triangle ABD
sin35° = =
=
( multiply both sides by BD )
BD × sin35° = 12 ( divide both sides by sin35° )
BD = ≈ 20.92 cm
using the sine rule in Δ BCD
=
, that is
=
( cross- multiply )
CD × sin52° = 20.92 × sin102° ( divide both sides by sin52° )
CD = ≈ 26.0 cm ( to 3 significant figures )
Answer:
Step-by-step explanation:
strategy: find the distance of the two points, take half of that, b/c that will be the radius, Then use the area of a circle formula to find the answer
P1 = (1,-1) in the form (x1,y1)
P2= ((3,3) in the form (x2,y2)
dist = sqrt [ (x2-x1)^2 + (y2-y1)^2 ]
dist = sqrt [ 3 -1 )^2 + 3-(-1)^2 ]
dist = sqrt [ 2^2 + 4^2 ]
dist = sqrt [ 4 + 16 ]
dist = sqrt [20]
r = /2
area of circle =
area of circle = (
/2)^2
area of circle = (
/2)(
/2)
area of circle = (20 / 4)
area of circle = 5
area of circle = 5