Answer:
Function sparse code is
def sparse(a):
rl = []
cl = []
for i in range(0,len(a)):
rl.append(a[i][1])
cl.append(a[i][2])
r = max(rl)
c = max(cl)
s = []
k = 0
for i in range(0,r+1):
s.append([])
for j in range(0,c+1):
if (i==a[k][1]) & (j == a[k][2]):
s[i].append(a[k][0])
k = k+1
else:
s[i].append(0)
return s
def main():
k = sparse([[3,1,2],[4,5,3]])
print(k)
if __name__ == '__main__':
main()
Explanation:
Please see attachment for output
Answer: 37.1
Explanation: The Law of sines states that there is a proportionality between a side of triangle and its correspondent angle, i.e.:

where:
a, b and c are sides
A, B and C are angles
In the question, there is a triangle with 27.4 as a measure of side a, angles A and C. So, it wants the side c:


c = 
c = 37.1
The side c is 37.1
Answer:
Full Record - A screen containing complete or detailed citation information which may include a summary or abstract. Full Text - A term to describe articles that can be displayed in their entirety, as opposed to Abstract and References only.
Explanation:
Answer:
The correct answer to the following question will be "Checksum".
Explanation:
A variable that reflects the amount of several bits in a transmitted packet and is used by practitioners of IT to spot heavy-level anomalies in the transmission of data, known as Checksum.
- After executing a cryptographic hashing algorithm each piece of information or a document could be allocated a value of checksum before delivery.
- We are relevant because we are using them to verify the authenticity of the documents.
So, it's the right answer.
Answer:
A. days of vacation time left
B. days of school left in the year
D. years of service someone performed
Explanation:
The NETWORKDAYS function is a built in excel function which makes it easy to calculate the number of days between two specified dates the start date and the end date, this function when applied excludes weekends from the days calculated and one has the opportunity of specifying certain holidays. With this function. The number of days till vacation, the number school days left. The NETWORKDAYS is a very versatile function.