Answer:
1/4
Step-by-step explanation:
this should be it
(hope it helps)
Answer:
Two adult tickets and 5 student tickets
Step-by-step explanation:
Let a=adult tickets Let s=student tickets
You know that each adult ticket is $9.10 and each student ticket cost $7.75. At the end, it cost $56.95 for both students and adults so the first equation should be 9.10a+7.75s=56.95. To get the second equation, you know that Mrs. Williams purchased 7 tickets in total that were both students and adults. Therefore, the second equation should be a+s=7. The two equations are 9.10a+7.75s=56.95
a+s=7.
Now, use substitution to solve this. I will isolate s from this equation so the new equation should be s=-a+7. Plug in this equation to the other equation, it will look like this 9.10a+7.75(-a+7)=56.95. Simplify this to get 9.10a-7.75a+54.25=56.95. Simplify this again and the equation will become 1.35a=2.70. Then divide 1.35 by each side to get a=2. This Mrs. Williams bought two adult tickets. Plug in 2 into a+s=7, it will look like this (2)+s=7. Simplify this and get s=5. This means Mrs. Williams bought five adult tickets. Therefore she bought 2 adult tickets and 5 student tickets.
Hope this helps
Step-by-step explanation:
if the 2 matrices are inverse, then their product must be the identity matrix
1 0
0 1
so,
m×3 + 2×-7 = 1
7×3 + 3×-7 = 0
m×-2 + 2×m = 0
7×-2 + 3×m = 1
that means we have to solve only
3m - 14 = 1
3m = 15
m = 5
Answer:
2
Step-by-step explanation:
Answer:
3/14
Step-by-step explanation:
You basically flip the numbers around. Hope this helps!
