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Nikitich [7]
3 years ago
6

Miguel Rodriguez Borrowed $400 from his brother Julio to pay for books and tuition. He agreed to pay Julio in 6 months with simp

le annual interests at 6.8% How much will the interest amount to what amount must Miguel pay Julio at the end of 6 months
Mathematics
2 answers:
DENIUS [597]3 years ago
8 0

The simple interest is calculated as :

S.I = P*T*R

where S.I is the simple interest to be calculated

P = Principal

T = Time period in years

R = Annual interest rate

The the above problem,

Amount borrowed which would be the principal (P) = $400

Time period = 6 months = 1/2 year

Annual interest rate = 6.8% = 6.8/100 = 0.068

Simple Interest = P*T*R

Simple Interest = 400*1/2*0.068 = 200 *0.068

Simple Interest = $13.6

The simple interest amount that Miguel must pay to Julio at the end of six months is $13.6

poizon [28]3 years ago
5 0

Answer:

13.00

Step-by-step explanation:

That is only if the annual interest is 6.3

and the final was $413.00

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Answer:

4n+(2n-9)

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First, I wrote the fraction as 1 63/100. I believe this is simplest form so the numerator is 63.

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A scale drawing has a scale of 5mm : 1cm. What is the scale factor?
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A phone company charges a flat rate of $15 to make phone calls for a month.they charge $0.10 per minute for each call made.if th
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450 minutes

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Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

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3 years ago
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