212°F
147°F
23.2 min
1) Initial temperature for t=0
T(0)=68+144e^(0)=68+144=212°F
2) After 15 min
T(15)=68+144e^(-0.04*15)=68+144e^(-0.6)=147°F
3) 125°F -> t=?
125=68+144e^(-0.04t)
144e^(-0.04t)=125-68=57
e^(-0.04t)=57/144=0.4 you can apply ln on both sides:
-0.04t=ln(0.4) solving you get t=23.3 min
Answer:
6x+10
Step-by-step explanation:
2x×2(2x+5)
2x+4x+10
6x+10
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a cross section is the intersection of a solid and a plane.
Step-by-step explanation:
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(3,0)
Step-by-step explanation: