Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let 
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.
![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)
So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
The way you put it is confusing. I'll answer but the way you put it was confusing to me.
7,874 inches is the answer
Hope this helps!!!
Answer:
(-2,3)
Step-by-step explanation:
For the point to be 2/3 of the way; it means it divides AB into the ratio 2 to 1
Now, we can use the internal section formula to get the coordinates of this point
(x,y) = (nx1 + mx2)/(m + n), (ny1 + my2)/(m + n)
where (m,n) = (2,1)
(x1,y1) = (-4,-1)
(x2,y2) = (5,5)
(x,y) = (1(-4) + 2(-1)/(1+2), (1(-1)+2(5)/(1+2)
(x,y) = (-4-2)/3, (-1 + 10)/3
(x,y) = (-2,3)
