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vovangra [49]
3 years ago
9

Rebecca and Megan are shopping at a store that sells jewelry, scarves, and purses. The cost of all the items at the store includ

e tax.
Mathematics
1 answer:
kow [346]3 years ago
7 0
If they are browsing then the answer would be $0-$300 but if they came there to get a specific thing; then it would cost $30-$50 I hoped this helped ^^
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Simplify the expression. 2+2^2÷4+3 6 7 21 67
True [87]

Answer:

6

Step-by-step explanation:

2+2^2÷4+3

PEMDAS says exponents first

2+4÷4+3

Then multiply and divide from left to right

2+1+3

Then add and subtract

6

3 0
4 years ago
If the units digit of the three-digit positive integer k is nonzero, what is the tens digit of k ?
Vanyuwa [196]

Answer:

  any digit 0 to 9

Step-by-step explanation:

Nothing about your description of the number suggests that the 10s digit depends on the units digit. The tens digit can be any digit 0 to 9.

8 0
3 years ago
A bag contain 3 black balls and 2 white balls.
Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\

b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

 =\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}

d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

a) Probability both black without replacement

  =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

b) Probability  of one black and one white

 =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

c) Probability of at least one black ( BB or BW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}

d) Probability of at most one black ( BW or WW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}

6 0
3 years ago
1. Ted found out that the rebate is not given until after he has
nadezda [96]

9514 1404 393

Answer:

  maybe not

Step-by-step explanation:

Consider a couple of scenarios for a $20,000 car purchase and a $2000 rebate, with sales tax at 10%.

1) The rebate is applied directly to the purchase price.

  Taxable amount: $20,000 -2,000 = $18,000.

  Price with tax: $18,000 × 1.10 = $19,800

  Amount financed: $19,800.

__

2) The rebate is given after the sale is complete.

  Taxable amount: $20,000

  Price with tax: $20,000 × 1.10 = $22,000

  Amount financed: $22,000

  Remaining loan balance if $2000 rebate is immediately applied to the loan: $22,000 -$2000 = $20,000

__

If the loan is for 5 years at 3%, the payments and total costs are ...

  Scenario 1: Monthly payment $355.78;

     total cost of loan: 60×355.78 = 21,346.80

  Scenario 2: Monthly payment $395.31;

     total cost of loan: 55×395.31 = $21,742.05  (note there are fewer payments because of the initial payment to principal of $2000)

__

Ted effectively has to finance an additional $200, equal to the sales tax on the rebate. So the delayed rebate costs him an extra $395.25 over the life of the loan.

_____

We have assumed certain tax and payment scenarios. If tax is not an issue, and if the loan terms are such that the rebate can be applied immediately to the loan amount, then <em>there may be no difference in total cost</em>, or the delayed rebate may result in a <em>lower</em> total cost due to the higher monthly payment.

7 0
3 years ago
Use the permutation formula to solve a problem when
rodikova [14]
B B B B B B B B B B B B B B B B B

8 0
2 years ago
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